Solve the Problem $y \left( 36 + 4 x ^ { 2 } \right) = 2 , x = 0 , y = 0$

Multiple Choice

Solve the problem.
-Find the area bounded by $y \left( 36 + 4 x ^ { 2 } \right) = 2 , x = 0 , y = 0$ , and $x = 4$ .

A) $\sin ^ { - 1 } \left( \frac { 4 } { 3 } \right)$
B) $2 \sin ^ { - 1 } \left( \frac { 4 } { 3 } \right)$
C) $\frac { 1 } { 6 } \tan ^ { - 1 } \left( \frac { 2 } { 3 } \right)$
D) $\frac { 1 } { 6 } \tan ^ { - 1 } \left( \frac { 4 } { 3 } \right)$