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Solve the Differential Equation dydx=3x2cos⁡2y\frac { d y } { d x } = 3 x ^ { 2 } \cos ^ { 2 } y

Question 111

Multiple Choice

Solve the differential equation.
- dydx=3x2cos⁡2y\frac { d y } { d x } = 3 x ^ { 2 } \cos ^ { 2 } y


A) y=x3+Cy = x ^ { 3 } + C
B) y=tan⁡−1(x3+C) y = \tan ^ { - 1 } \left( x ^ { 3 } + C \right)
C) y=tan⁡−1(x2+C) y = \tan ^ { - 1 } \left( x ^ { 2 } + C \right)
D) y=tan⁡(x3+C) y = \tan \left( x ^ { 3 } + C \right)

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