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Provide an Appropriate Response limxln(x+1)lnx=limxln(x+9982)lnx\lim _ { x \rightarrow } \frac { \ln ( x + 1 ) } { \ln x } = \lim _ { x \rightarrow } \frac { \ln ( x + 9982 ) } { \ln x }

Question 128

Essay

Provide an appropriate response.
-Show that limxln(x+1)lnx=limxln(x+9982)lnx\lim _ { x \rightarrow } \frac { \ln ( x + 1 ) } { \ln x } = \lim _ { x \rightarrow } \frac { \ln ( x + 9982 ) } { \ln x } . Explain why this is the case.

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