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The Position Vector of a Particle Is R(t) t=1t = 1

Question 129

Multiple Choice

The position vector of a particle is r(t) . Find the requested vector.
-The acceleration at t=1t = 1 for r(t) =t5i+7ln(14+t) j+3tk\mathbf { r } ( \mathrm { t } ) = \mathrm { t } ^ { 5 } \mathbf { i } + 7 \ln \left( \frac { 1 } { 4 + \mathrm { t } } \right) \mathbf { j } + \frac { 3 } { \mathrm { t } } \mathbf { k }


A) a(1) =20i7j6k\mathbf { a } ( 1 ) = 20 \mathbf { i } - 7 \mathbf { j } - 6 \mathbf { k }
B) a(1) =20i+725j+6k\mathbf { a } ( 1 ) = 20 \mathbf { i } + \frac { 7 } { 25 } \mathbf { j } + 6 \mathbf { k }
C) a(1) =20i+725j6k\mathbf { a } ( 1 ) = 20 \mathbf { i } + \frac { 7 } { 25 } \mathbf { j } - 6 \mathbf { k }
D) a(1) =20i+7j+6k\mathbf { a } ( 1 ) = 20 \mathbf { i } + 7 \mathbf { j } + 6 \mathbf { k }

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