Solved

The Position Vector of a Particle Is R(t) t=0t = 0

Question 122

Multiple Choice

The position vector of a particle is r(t) . Find the requested vector.
-The acceleration at t=0t = 0 for r(t) =t2i+(8t310) j+43tkr ( t ) = t ^ { 2 } i + \left( 8 t ^ { 3 } - 10 \right) j + \sqrt { 4 - 3 t } k


A) a(0) =2i332k\mathbf { a } ( 0 ) = 2 \mathbf { i } - \frac { 3 } { 32 } \mathbf { k }
B) a(0) =2i+932k\mathbf { a } ( 0 ) = 2 \mathbf { i } + \frac { 9 } { 32 } \mathbf { k }
C) a(0) =2i98k\mathbf { a } ( 0 ) = 2 \mathbf { i } - \frac { 9 } { 8 } \mathbf { k }
D) a(0) =2i932k\mathbf { a } ( 0 ) = 2 \mathbf { i } - \frac { 9 } { 32 } \mathbf { k }

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions