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Question 48

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Provide an appropriate response.
-  Prove that if v and u are differentiable functions of t, then ddt(u+v)=dudt+dvdt\text { Prove that if } \mathbf { v } \text { and } \mathbf { u } \text { are differentiable functions of } t \text {, then } \frac { \mathrm { d } } { \mathrm { dt } } ( \mathbf { u } + \mathbf { v } ) = \frac { \mathrm { d } \mathbf { u } } { \mathrm { dt } } + \frac { \mathrm { d } \mathbf { v } } { \mathrm { dt } } \text {. }

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verifed

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\[\begin{array} { l }
\frac { d } { d t...

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