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Find Two Values of Q That Satisfy the Equation Below (0θ2π)( 0 \leq \theta \leq 2 \pi )

Question 2

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Find two values of q that satisfy the equation below. Give values of q in radians (0θ2π) ( 0 \leq \theta \leq 2 \pi ) . Do not use a calculator. sin q = 32- \frac { \sqrt { 3 } } { 2 }


A) θ=π3,\theta = \frac { \pi } { 3 }, θ=5π3\theta = \frac { 5 \pi } { 3 }
B) θ=π3,\theta = \frac { \pi } { 3 }, θ=π\theta = \pi
C) θ=4π3\theta = \frac { 4 \pi } { 3 } , θ=5π3\theta = \frac { 5 \pi } { 3 }
D) θ=π6,\theta = \frac { \pi } { 6 }, θ=7π6\theta = \frac { 7 \pi } { 6 }
E) θ=π3\theta = \frac { \pi } { 3 } , θ=5π3\theta = \frac { 5 \pi } { 3 }

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