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Solve the Equation Below For θ\theta (0θ2π)( 0 \leq \theta \leq 2 \pi )

Question 1

Multiple Choice

Solve the equation below for θ\theta (0θ2π) ( 0 \leq \theta \leq 2 \pi ) . For some of the equations you should use the trigonometric identities listed in this section. Use the trace feature of a graphing utility to verify your results. sin2θcosθ=0\sin 2 \theta - \cos \theta = 0


A) π4,5π4\frac { \pi } { 4 } , \frac { 5 \pi } { 4 }
B) π4,3π4,5π4,7π4\frac { \pi } { 4 } , \frac { 3 \pi } { 4 } , \frac { 5 \pi } { 4 } , \frac { 7 \pi } { 4 }
C) π6,5π6,3π6\frac { \pi } { 6 } , \frac { 5 \pi } { 6 } , \frac { 3 \pi } { 6 }
D) π6,5π6,π2,3π2\frac { \pi } { 6 } , \frac { 5 \pi } { 6 } , \frac { \pi } { 2 } , \frac { 3 \pi } { 2 }
E) π6,5π6,7π6\frac { \pi } { 6 } , \frac { 5 \pi } { 6 } , \frac { 7 \pi } { 6 }

Correct Answer:

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