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Use Integration by Parts to Find the Indefinite Integral xcos2xdx\int x \cos 2 x d x

Question 3

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Use integration by parts to find the indefinite integral. xcos2xdx\int x \cos 2 x d x


A) 12xcos2x14sin2x+C\frac { 1 } { 2 } x \cos 2 x - \frac { 1 } { 4 } \sin 2 x + C
B) 12xsin2x14cos2x+C\frac { 1 } { 2 } x \sin 2 x - \frac { 1 } { 4 } \cos 2 x + C
C) 12sin2x+12cos2x+C\frac { 1 } { 2 } \sin 2 x + \frac { 1 } { 2 } \cos 2 x + C
D) 12xsin2x+14cos2x+C\frac { 1 } { 2 } x \sin 2 x + \frac { 1 } { 4 } \cos 2 x + C  Use integration by parts to find the indefinite integral.  \int x \cos 2 x d x  A)   \frac { 1 } { 2 } x \cos 2 x - \frac { 1 } { 4 } \sin 2 x + C  B)   \frac { 1 } { 2 } x \sin 2 x - \frac { 1 } { 4 } \cos 2 x + C  C)   \frac { 1 } { 2 } \sin 2 x + \frac { 1 } { 2 } \cos 2 x + C  D)   \frac { 1 } { 2 } x \sin 2 x + \frac { 1 } { 4 } \cos 2 x + C    E)   \frac { 1 } { 4 } x \cos 2 x + \frac { 1 } { 2 } \sin 2 x + C
E) 14xcos2x+12sin2x+C\frac { 1 } { 4 } x \cos 2 x + \frac { 1 } { 2 } \sin 2 x + C

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