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Find an Equation of the Tangent Line to the Graph y=log3xy = \log _ { 3 } x

Question 72

Multiple Choice

Find an equation of the tangent line to the graph of y=log3xy = \log _ { 3 } x at the point (27,3) ( 27,3 ) .


A) y=3+1ln3(x27) y = 3 + \frac { 1 } { \ln 3 } ( x - 27 )
B) y=3+13ln27(x27) y = 3 + \frac { 1 } { 3 \ln 27 } ( x - 27 )
C) y=3+127ln3(x27) y = 3 + \frac { 1 } { 27 \ln 3 } ( x - 27 )
D) y=3+127(x27) y = 3 + \frac { 1 } { 27 } ( x - 27 )
E) none of the above

Correct Answer:

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