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Solve the Compound Inequality $4 ( x + 1 ) \leq 3 ( x + 2 )$

Question 177

Multiple Choice

Solve the compound inequality. Graph the solution set (if one exists) and write it using interval notation. $4 ( x + 1 ) \leq 3 ( x + 2 )$ and $x + 12 < - 3$

A) $( - \infty , 2 ]$
$Solve the compound inequality. Graph the solution set (if one exists) and write it using interval notation. 4 ( x + 1 ) \leq 3 ( x + 2 ) and x + 12 < - 3 A) ( - \infty , 2 ] B) [ - 15,2 ] C) ( - 15,2 ] D) ( - 15,2 ) E) ( - \infty , - 15 )$
B) $[ - 15,2 ]$
$Solve the compound inequality. Graph the solution set (if one exists) and write it using interval notation. 4 ( x + 1 ) \leq 3 ( x + 2 ) and x + 12 < - 3 A) ( - \infty , 2 ] B) [ - 15,2 ] C) ( - 15,2 ] D) ( - 15,2 ) E) ( - \infty , - 15 )$
C) $( - 15,2 ]$
$Solve the compound inequality. Graph the solution set (if one exists) and write it using interval notation. 4 ( x + 1 ) \leq 3 ( x + 2 ) and x + 12 < - 3 A) ( - \infty , 2 ] B) [ - 15,2 ] C) ( - 15,2 ] D) ( - 15,2 ) E) ( - \infty , - 15 )$
D) $( - 15,2 )$
$Solve the compound inequality. Graph the solution set (if one exists) and write it using interval notation. 4 ( x + 1 ) \leq 3 ( x + 2 ) and x + 12 < - 3 A) ( - \infty , 2 ] B) [ - 15,2 ] C) ( - 15,2 ] D) ( - 15,2 ) E) ( - \infty , - 15 )$
E) $( - \infty , - 15 )$
$Solve the compound inequality. Graph the solution set (if one exists) and write it using interval notation. 4 ( x + 1 ) \leq 3 ( x + 2 ) and x + 12 < - 3 A) ( - \infty , 2 ] B) [ - 15,2 ] C) ( - 15,2 ] D) ( - 15,2 ) E) ( - \infty , - 15 )$

Solve the Compound Inequality 4(x+1)≤3(x+2)4 ( x + 1 ) \leq 3 ( x + 2 )4(x+1)≤3(x+2)

Multiple Choice

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Solve the Compound Inequality $4 ( x + 1 ) \leq 3 ( x + 2 )$

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