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Let V Be the Volume of the Solid That Lies y=9x2y = - \sqrt { 9 - x ^ { 2 } }

Question 103

Multiple Choice

Let V be the volume of the solid that lies between planes perpendicular to the x-axis from x = -3 to x = 3. The cross-sections of this solid perpendicular to the x-axis run from y=9x2y = - \sqrt { 9 - x ^ { 2 } } to y=9x2y = \sqrt { 9 - x ^ { 2 } } and they are equilateral triangles with bases in the xy-plane. Then V is


A) 18218 \sqrt { 2 }
B) 36336 \sqrt { 3 }
C) 36
D) 18518 \sqrt { 5 }
E) 9

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