Solved

Let y=u+1uy = u + \frac { 1 } { u }

Question 98

Multiple Choice

Let y=u+1uy = u + \frac { 1 } { u } and u=x2+x1u = x ^ { 2 } + x - 1 By the Chain Rule, dydx\frac { d y } { d x } is


A) 1+1x2+x11 + \frac { 1 } { x ^ { 2 } + x - 1 }
B) 11x2+x11 - \frac { 1 } { x ^ { 2 } + x - 1 }
C) 11(x2+x1) 21 - \frac { 1 } { \left( x ^ { 2 } + x - 1 \right) ^ { 2 } }
D) (2x+1) (11(x2+x1) 2) ( 2 x + 1 ) \left( 1 - \frac { 1 } { \left( x ^ { 2 } + x - 1 \right) ^ { 2 } } \right)
E) (2x+1) (1+1(x2+x1) 2) ( 2 x + 1 ) \left( 1 + \frac { 1 } { \left( x ^ { 2 } + x - 1 \right) ^ { 2 } } \right)

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions