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Letting f(x)=xf ( x ) = \sqrt { x } And x0=25,x _ { 0 } = 25 ,

Question 23

Multiple Choice

Letting f(x) =xf ( x ) = \sqrt { x } and x0=25,x _ { 0 } = 25 , the approximation of 25.1\sqrt { 25.1 } by differentials is


A) 5.1
B) 5.05
C) 5.01
D) 4.99
E) 4.95

Correct Answer:

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