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A Solution Of y=x2y3y ^ { \prime } = x ^ { 2 } y ^ { 3 }

Question 30

Multiple Choice

A solution of y=x2y3y ^ { \prime } = x ^ { 2 } y ^ { 3 } is


A) 2x3+3y2=5- 2 x ^ { 3 } + 3 y ^ { - 2 } = 5
B) 2x3+3y2=52 x ^ { 3 } + 3 y ^ { - 2 } = 5
C) 2x33y2=52 x ^ { 3 } - 3 y ^ { - 2 } = 5
D) 3x3+2y2=53 x ^ { 3 } + 2 y ^ { - 2 } = 5
E) 3x32y2=53 x ^ { 3 } - 2 y ^ { - 2 } = 5

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