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Let f(x,y,z)=xyzf ( x , y , z ) = x y z

Question 16

Multiple Choice

Let f(x,y,z) =xyzf ( x , y , z ) = x y z with constraint x+y+z=1x + y + z = 1 . Assume that x,y,z0x , y , z \geq 0 . Then f has a relative maximum at


A) (13,16,12) \left( \frac { 1 } { 3 } , \frac { 1 } { 6 } , \frac { 1 } { 2 } \right)
B) (13,12,16) \left( \frac { 1 } { 3 } , \frac { 1 } { 2 } , \frac { 1 } { 6 } \right)
C) (12,16,13) \left( \frac { 1 } { 2 } , \frac { 1 } { 6 } , \frac { 1 } { 3 } \right)
D) (13,13,13) \left( \frac { 1 } { 3 } , \frac { 1 } { 3 } , \frac { 1 } { 3 } \right)
E) (12,13,16) \left( \frac { 1 } { 2 } , \frac { 1 } { 3 } , \frac { 1 } { 6 } \right)

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