Solved

Let Then F Is

A)Continuous at (0,1,0)
B)Discontinuous at \left

Question 73

Multiple Choice

Let f(x,y,z) ={1x2+z2(x,z) (0,0) 0(x,z) =(0,0) f ( x , y , z ) = \left\{ \begin{array} { c c } \frac { 1 } { x ^ { 2 } + z ^ { 2 } } & ( x , z ) \neq ( 0,0 ) \\0 & ( x , z ) = ( 0,0 ) \end{array} \right. . Then f is


A) Continuous at (0,1,0)
B) Discontinuous at (0,1,0) because f is undefined at (0,1,0)
C) Discontinuous at (0,1,0) because the limit of f at (0,1,0) does not exist
D) Discontinuous at (0,1,0) because the limit of f at (0,1,0) is different from the function values at (0,1,0)
E) Discontinuous at (0,1,0) for a reason that is different from the ones above

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions