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Let r(t)=sin(2t)i+2tjcos(2t)k\mathbf { r } ( t ) = - \sin ( 2 t ) \mathbf { i } + 2 t \mathbf { j } - \cos ( 2 t ) \mathbf { k }

Question 90

Multiple Choice

Let r(t) =sin(2t) i+2tjcos(2t) k\mathbf { r } ( t ) = - \sin ( 2 t ) \mathbf { i } + 2 t \mathbf { j } - \cos ( 2 t ) \mathbf { k } Then the unit normal vector n(π6) \mathbf { n } \left( \frac { \pi } { 6 } \right) is


A) 12i+32k\frac { 1 } { 2 } \mathbf { i } + \frac { \sqrt { 3 } } { 2 } \mathbf { k }
B) 32i12k- \frac { \sqrt { 3 } } { 2 } \mathbf { i } - \frac { 1 } { 2 } \mathbf { k }
C) 32i+12k\frac { \sqrt { 3 } } { 2 } \mathbf { i } + \frac { 1 } { 2 } \mathbf { k }
D) 32i12k\frac { \sqrt { 3 } } { 2 } \mathbf { i } - \frac { 1 } { 2 } \mathbf { k }
E) 32i+12k- \frac { \sqrt { 3 } } { 2 } \mathbf { i } + \frac { 1 } { 2 } \mathbf { k }

Correct Answer:

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