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The Radius of Curvature Of r(t)=costi+sintj+tk\mathbf { r } ( t ) = \cos t \mathbf { i } + \sin t \mathbf { j } + t \mathbf { k }

Question 88

Multiple Choice

The radius of curvature of r(t) =costi+sintj+tk\mathbf { r } ( t ) = \cos t \mathbf { i } + \sin t \mathbf { j } + t \mathbf { k } at the point corresponding to t=π2t = \frac { \pi } { 2 } is


A) 21717\frac { 2 } { 17 \sqrt { 17 } }
B) 122\frac { 1 } { 2 \sqrt { 2 } }
C) 2
D) 10110112\frac { 101 \sqrt { 101 } } { 12 }
E) 7125\frac { 7 } { 125 }

Correct Answer:

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