Solved

The Radius of Curvature Of r(t)=cos(2t)i+sin(2t)j+tk\mathbf { r } ( t ) = \cos ( 2 t ) \mathbf { i } + \sin ( 2 t ) \mathbf { j } + t \mathbf { k }

Question 74

Multiple Choice

The radius of curvature of r(t) =cos(2t) i+sin(2t) j+tk\mathbf { r } ( t ) = \cos ( 2 t ) \mathbf { i } + \sin ( 2 t ) \mathbf { j } + t \mathbf { k } at the point corresponding to t = 0 is


A) 424 \sqrt { 2 }
B) 122\frac { 1 } { 2 \sqrt { 2 } }
C) 2
D) 32\frac { 3 } { \sqrt { 2 } }
E) 5
4

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions