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Consider the Following Periodic Function with Period :
F $a_{n}=\frac{1}{(2 n-1) \pi}, n=1,2,3, \ldots$

Question 4

Multiple Choice

Consider the following periodic function with period $Consider the following periodic function with period : F (t) = F = f (t) The Fourier representation has the form Which of these are the coefficients ? A) a_{n}=\frac{1}{(2 n-1) \pi}, n=1,2,3, \ldots B) a_{n}=-\frac{2}{\pi} \cdot \frac{1}{2 n-1}, n=1,2,3, \ldots C) a_{2 n}=0, a_{2 n-1}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, n=1,2,3, \ldots D) a_{2 n}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, a_{2 n-1}=0, n=1,2,3, \ldots E) a_{n}=0, n=1,2,3, \ldots$ :
F (t) = $Consider the following periodic function with period : F (t) = F = f (t) The Fourier representation has the form Which of these are the coefficients ? A) a_{n}=\frac{1}{(2 n-1) \pi}, n=1,2,3, \ldots B) a_{n}=-\frac{2}{\pi} \cdot \frac{1}{2 n-1}, n=1,2,3, \ldots C) a_{2 n}=0, a_{2 n-1}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, n=1,2,3, \ldots D) a_{2 n}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, a_{2 n-1}=0, n=1,2,3, \ldots E) a_{n}=0, n=1,2,3, \ldots$
F $Consider the following periodic function with period : F (t) = F = f (t) The Fourier representation has the form Which of these are the coefficients ? A) a_{n}=\frac{1}{(2 n-1) \pi}, n=1,2,3, \ldots B) a_{n}=-\frac{2}{\pi} \cdot \frac{1}{2 n-1}, n=1,2,3, \ldots C) a_{2 n}=0, a_{2 n-1}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, n=1,2,3, \ldots D) a_{2 n}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, a_{2 n-1}=0, n=1,2,3, \ldots E) a_{n}=0, n=1,2,3, \ldots$ = f (t)
The Fourier representation has the form $Consider the following periodic function with period : F (t) = F = f (t) The Fourier representation has the form Which of these are the coefficients ? A) a_{n}=\frac{1}{(2 n-1) \pi}, n=1,2,3, \ldots B) a_{n}=-\frac{2}{\pi} \cdot \frac{1}{2 n-1}, n=1,2,3, \ldots C) a_{2 n}=0, a_{2 n-1}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, n=1,2,3, \ldots D) a_{2 n}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, a_{2 n-1}=0, n=1,2,3, \ldots E) a_{n}=0, n=1,2,3, \ldots$
Which of these are the coefficients $Consider the following periodic function with period : F (t) = F = f (t) The Fourier representation has the form Which of these are the coefficients ? A) a_{n}=\frac{1}{(2 n-1) \pi}, n=1,2,3, \ldots B) a_{n}=-\frac{2}{\pi} \cdot \frac{1}{2 n-1}, n=1,2,3, \ldots C) a_{2 n}=0, a_{2 n-1}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, n=1,2,3, \ldots D) a_{2 n}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, a_{2 n-1}=0, n=1,2,3, \ldots E) a_{n}=0, n=1,2,3, \ldots$ ?

A) $a_{n}=\frac{1}{(2 n-1) \pi}, n=1,2,3, \ldots$
B) $a_{n}=-\frac{2}{\pi} \cdot \frac{1}{2 n-1}, n=1,2,3, \ldots$
C) $a_{2 n}=0, a_{2 n-1}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, n=1,2,3, \ldots$
D) $a_{2 n}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, a_{2 n-1}=0, n=1,2,3, \ldots$
E) $a_{n}=0, n=1,2,3, \ldots$

Consider the Following Periodic Function with Period : F an=1(2n−1)π,n=1,2,3,… a_{n}=\frac{1}{(2 n-1) \pi}, n=1,2,3, \ldots an​=(2n−1)π1​,n=1,2,3,…

Multiple Choice

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Consider the Following Periodic Function with Period :
F $a_{n}=\frac{1}{(2 n-1) \pi}, n=1,2,3, \ldots$

Correct Answer:
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