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An Oxygen Molecule Falls in a Vacuum

Question 7

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An oxygen molecule falls in a vacuum.From what height must it fall so that its kinetic energy at the bottom equals the average energy of an oxygen molecule at 800 K? (The Boltzmann constant is An oxygen molecule falls in a vacuum.From what height must it fall so that its kinetic energy at the bottom equals the average energy of an oxygen molecule at 800 K? (The Boltzmann constant is ,the molecular weight of oxygen is 32.0 g/mol,and Avogadro's number is A) 31.8 km B) 10.6 km C) 21.1 km D) 42.3 km ,the molecular weight of oxygen is 32.0 g/mol,and Avogadro's number is An oxygen molecule falls in a vacuum.From what height must it fall so that its kinetic energy at the bottom equals the average energy of an oxygen molecule at 800 K? (The Boltzmann constant is ,the molecular weight of oxygen is 32.0 g/mol,and Avogadro's number is A) 31.8 km B) 10.6 km C) 21.1 km D) 42.3 km


A) 31.8 km
B) 10.6 km
C) 21.1 km
D) 42.3 km

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