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The Solution Of xy′=(x−1)y2x y ^ { \prime } = ( x - 1 ) y ^ { 2 }

Question 2

Multiple Choice

The solution of xy′=(x−1) y2x y ^ { \prime } = ( x - 1 ) y ^ { 2 } is


A) y=1/(x+ln⁡x+c) y = 1 / ( x + \ln x + c )
B) y=1/(x−ln⁡x+c) y = 1 / ( x - \ln x + c )
C) y=−c/(x+ln⁡x) y = - c / ( x + \ln x )
D) y=−c/(x−ln⁡x) y = - c / ( x - \ln x )
E) y=−1/(x−ln⁡x+c) y = - 1 / ( x - \ln x + c )

Correct Answer:

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