The Solution of the Previous Problem Is
A) $y = w _ { 0 } \left[ 4 ( t - 5 ) ^ { 3 } u ( t - 5 ) + 15 t ^ { 2 } - 2 t ^ { 3 } \right] / ( 24 E I )$

Multiple Choice

The solution of the previous problem is

A) $y = w _ { 0 } \left[ 4 ( t - 5 ) ^ { 3 } u ( t - 5 ) + 15 t ^ { 2 } - 2 t ^ { 3 } \right] / ( 24 E I )$
B) $y = w _ { 0 } \left[ 4 ( t - 5 ) ^ { 3 } u ( t - 5 ) + 15 t ^ { 2 } - 2 t ^ { 3 } \right] / ( 12 E I )$
C) $y = w _ { 0 } E I \left[ 4 ( t - 5 ) ^ { 3 } u ( t - 5 ) + 15 t ^ { 2 } - 2 t ^ { 3 } \right] / 24$
D) $y = w _ { 0 } E I \left[ 4 ( t - 5 ) ^ { 3 } u ( t - 5 ) - 15 t ^ { 2 } - 2 t ^ { 3 } \right] / 12$
E) $y = w _ { 0 } \left[ 4 ( t - 5 ) ^ { 3 } u ( t - 5 ) - 15 t ^ { 2 } - 2 t ^ { 3 } \right] / ( 24 E I )$