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In the Previous Problem, the Solution Is
A) U=u0(1+ekα2t)U = u _ { 0 } \left( 1 + e ^ { - k \alpha ^ { 2 } t } \right)

Question 7

Multiple Choice

In the previous problem, the solution is


A) U=u0(1+ekα2t) U = u _ { 0 } \left( 1 + e ^ { - k \alpha ^ { 2 } t } \right)
B) U=u0(1ekα2t) U = u _ { 0 } \left( 1 - e ^ { - k \alpha ^ { 2 } t } \right)
C) U=u0(1+ekα2t) /αU = u _ { 0 } \left( 1 + e ^ { - k \alpha ^ { 2 } t } \right) / \alpha
D) U=u0(1ekα2t) /αU = u _ { 0 } \left( 1 - e ^ { - k \alpha ^ { 2 } t } \right) / \alpha
E) U=u0(1ekα2t) /α2U = u _ { 0 } \left( 1 - e ^ { - k \alpha ^ { 2 } t } \right) / \alpha ^ { 2 }

Correct Answer:

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