The Solution of the Previous Problem Is
A) $y = c _ { 1 } P _ { 3 } ( x ) + c _ { 2 } P _ { - 3 } ( x )$

Multiple Choice

The solution of the previous problem is

A) $y = c _ { 1 } P _ { 3 } ( x ) + c _ { 2 } P _ { - 3 } ( x )$
B) $y = c _ { 1 } P _ { 3 } ( x ) + c _ { 2 } Q _ { 3 } ( x )$ , where $Q _ { 3 } ( x )$ is given by an infinite series
C) $y = c _ { 1 } J _ { 4 } ( x ) + c _ { 2 } Y _ { 4 } ( x )$
D) $y = c _ { 1 } J _ { 3 } ( x ) + c _ { 2 } Y _ { 3 } ( x )$
E) $y = c _ { 1 } J _ { 12 } ( x ) + c _ { 2 } Y _ { 12 } ( x )$