Solved

Find an Equation of the Tangent Plant to the Surface z=xy+1z = \frac { x } { y + 1 }

Question 204

Multiple Choice

Find an equation of the tangent plant to the surface z=xy+1z = \frac { x } { y + 1 } at the point (1,4,15) \left( 1,4 , \frac { 1 } { 5 } \right) .


A) z=15x+125y+425z = \frac { 1 } { 5 } x + \frac { 1 } { 25 } y + \frac { 4 } { 25 }

B) z=15x125y425z = - \frac { 1 } { 5 } x - \frac { 1 } { 25 } y - \frac { 4 } { 25 }
C) z=15x125y425z = \frac { 1 } { 5 } x - \frac { 1 } { 25 } y - \frac { 4 } { 25 }
D)
z=15x125y+425z = \frac { 1 } { 5 } x - \frac { 1 } { 25 } y + \frac { 4 } { 25 }
E) z=15x125y+425z = - \frac { 1 } { 5 } x - \frac { 1 } { 25 } y + \frac { 4 } { 25 }
F) z=15x+125y425z = \frac { 1 } { 5 } x + \frac { 1 } { 25 } y - \frac { 4 } { 25 }

G) z=125x15y425z = \frac { 1 } { 25 } x - \frac { 1 } { 5 } y - \frac { 4 } { 25 }

H) z=125x15y+425z = \frac { 1 } { 25 } x - \frac { 1 } { 5 } y + \frac { 4 } { 25 }

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions