Exam 6: Propositional Logic

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Statement 1H Given the following statement: (S ⊃ ∼ R) ⊃ (∼ S • R) -The truth table for Statement 1H has how many lines?

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Given the statement: ∼ (S • ∼ D) ∨ (D ⊃ S) This statement is:

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Statement 3G Given the following statement: [A • (B ∨ C)] ∨ [∼ (A • B) ∨ ∼ (A • C)] -Statement 3G is:

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S ? ?R NRSN\frac { \mathrm { N } \supset \sim \mathrm { R } } { \mathrm { S } \supset \mathrm { N } }

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(R ? ?T) • (D ? T) TTRD\frac { \sim \mathrm { T } \vee \mathrm { T } } { \sim \mathrm { R } \vee \sim \mathrm { D } }

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If Chrysler increases sales, then it is not the case that both Mercedes introduces a new model and Nissan lays off workers.

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P ? ?D PD\frac { \sim \mathrm { P } } { \sim \mathrm { D } }

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Given the argument: K ∨ B / K ≡ (D ∨ ∼ B) // K ⊃ D This argument is:

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Given the argument: R ∨ I / ∼ S ∨ (R ⊃ I) // S ⊃ I This argument is:

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(B ? ?T) • (?B ? N) \frac { \sim \mathrm { B } \vee \mathrm { B } } { \hline \mathrm { T } \vee \mathrm { N } }

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Hertz runs a sale or both Avis buys new cars and Budget lowers rates.

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Statement 1D Given the following statement: ∼ (H ⊃ A) ∨ (A ⊃ H) -Statement 1D is:

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Given the statements: R ⊃ (M ∨ ∼ C) / (P ∨ U) ⊃ C / M ⊃ ∼ P / R ≡ U These statements are:

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?H ? ?B BH\frac{\mathrm{B}}{\mathrm{H}}

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Given the argument: S ∨ L / L ⊃ ∼ S // S ∨ ∼ L This argument is:

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W WKK\frac{\sim \mathrm{W} \supset \sim \mathrm{K}}{\mathrm{K}}

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If dinosaur DNA has deteriorated, then it is impossible to recreate dinosaurs. If dinosaurs perished long ago, then dinosaur DNA has deteriorated. Hence, if dinosaurs perished long ago, then it is impossible to recreate them.

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Movado's offering an ivory dial is a sufficient condition for Breitling's having a ruby model if Gucci's offering a better warranty is a necessary condition for Fossil's being water resistant.

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If an indirect truth table requiring more than one line is constructed for either an argument or a series of statements and no contradiction is derived on the first line, then:

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K GKG\frac { \mathrm { G } \supset \sim \mathrm { K } } { \sim \mathrm { G } }

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