Exam 6: The Normal Distribution
Exam 1: Defining and Collecting Data205 Questions
Exam 2: Organizing and Visualizing Variables212 Questions
Exam 3: Numerical Descriptive Measures163 Questions
Exam 4: Basic Probability171 Questions
Exam 5: Discrete Probability Distributions117 Questions
Exam 6: The Normal Distribution144 Questions
Exam 7: Sampling Distributions127 Questions
Exam 8: Confidence Interval Estimation187 Questions
Exam 9: Fundamentals of Hypothesis Testing: One-Sample Tests177 Questions
Exam 10: Two-Sample Tests300 Questions
Exam 11: Chi-Square Tests128 Questions
Exam 12: Simple Linear Regression204 Questions
Exam 13: Multiple Regression307 Questions
Exam 14: Business Analytics254 Questions
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SCENARIO 6-2
John has two jobs.For daytime work at a jewelry store he is paid $15,000 per month, plus a commission.His monthly commission is normally distributed with mean $10,000 and standard deviation $2000.At night he works occasionally as a waiter, for which his monthly income is normally distributed with mean $1,000 and standard deviation $300.John's income levels from these two sources are independent of each other.
-Referring to Scenario 6-2, the probability is 0.10 that John's commission from the jewelry store is more than how much in a given month?
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The amount of time necessary for assembly line workers to complete a product is a normal variable with a mean of 15 minutes and a standard deviation of 2 minutes.So, 17% of the products would be assembled within minutes.
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SCENARIO 6-2
John has two jobs.For daytime work at a jewelry store he is paid $15,000 per month, plus a commission.His monthly commission is normally distributed with mean $10,000 and standard deviation $2000.At night he works occasionally as a waiter, for which his monthly income is normally distributed with mean $1,000 and standard deviation $300.John's income levels from these two sources are independent of each other.
-Referring to Scenario 6-2, John's income as a waiter will be between what two values symmetrically distributed around the population mean 80% of the time?
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SCENARIO 6-4
According to Investment Digest, the arithmetic mean of the annual return for common stocks over an
85-year period was 9.5% but the value of the variance was not mentioned.Also 25% of the annual returns were below 8% while 65% of the annual returns were between 8% and 11.5%.The article claimed that the distribution of annual return for common stocks was bell-shaped and approximately symmetric.Assume that this distribution is normal with the mean given above.Answer the following questions without the help of a calculator, statistical software or statistical table.
-Referring to Scenario 6-4, find the probability that the annual return of a random year will be more than 11.5%.
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Suppose Z has a standard normal distribution with a mean of 0 and standard deviation of 1.So,50% of the possible Z values are between and (symmetrically distributed about the mean).
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SCENARIO 6-2
John has two jobs.For daytime work at a jewelry store he is paid $15,000 per month, plus a commission.His monthly commission is normally distributed with mean $10,000 and standard deviation $2000.At night he works occasionally as a waiter, for which his monthly income is normally distributed with mean $1,000 and standard deviation $300.John's income levels from these two sources are independent of each other.
-Referring to Scenario 6-2, John's commission from the jewelry store will be between what two values symmetrically distributed around the population mean 80% of the time?
(Essay)
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You were told that the mean score on a statistics exam is 75 with the scores normally distributed.In addition, you know the probability of a score between 55 and 60 is 4.41% and that the probability of a score greater than 90 is 6.68%.What is the probability of a score between 60 and75?
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The true length of boards cut at a mill with a listed length of 10 feet is normally distributed with a mean of 123 inches and a standard deviation of 1 inch.What proportion of the boards will be over125 inches in length?
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The amount of time necessary for assembly line workers to complete a product is a normal variable with a mean of 15 minutes and a standard deviation of 2 minutes.The probability isthat a product is assembled in less than 20 minutes.
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The probability that a standard normal variable, Z, is between 1.50 and 2.10 is the same as the probability Z is between - 2.10 and - 1.50.
(True/False)
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The amount of tea leaves in a can from a production line is normally distributed with grams and grams.What is the probability that a randomly selected can will contain atleast 100 grams of tea leaves?
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Suppose Z has a standard normal distribution with a mean of 0 and standard deviation of 1.The probability that Z is between -2.33 and 2.33 is .
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SCENARIO 6-2
John has two jobs.For daytime work at a jewelry store he is paid $15,000 per month, plus a commission.His monthly commission is normally distributed with mean $10,000 and standard deviation $2000.At night he works occasionally as a waiter, for which his monthly income is normally distributed with mean $1,000 and standard deviation $300.John's income levels from these two sources are independent of each other.
-Referring to Scenario 6-2, for a given month, what is the probability that John's commission from the jewelry store is between $5,000 and $7,000?
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A normal probability plot may be used to assess the assumption of normality for a set of data.
(True/False)
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SCENARIO 6-2
John has two jobs.For daytime work at a jewelry store he is paid $15,000 per month, plus a commission.His monthly commission is normally distributed with mean $10,000 and standard deviation $2000.At night he works occasionally as a waiter, for which his monthly income is normally distributed with mean $1,000 and standard deviation $300.John's income levels from these two sources are independent of each other.
-Referring to Scenario 6-2, for a given month, what is the probability that John's commission from the jewelry store is less than $13,000?
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The amount of time necessary for assembly line workers to complete a product is a normal variable with a mean of 15 minutes and a standard deviation of 2 minutes.The probability isthat a product is assembled in between 14 and 16 minutes.
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Suppose Z has a standard normal distribution with a mean of 0 and standard deviation of 1.So,96% of the possible Z values are between and (symmetrically distributed about the mean).
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SCENARIO 6-2
John has two jobs.For daytime work at a jewelry store he is paid $15,000 per month, plus a commission.His monthly commission is normally distributed with mean $10,000 and standard deviation $2000.At night he works occasionally as a waiter, for which his monthly income is normally distributed with mean $1,000 and standard deviation $300.John's income levels from these two sources are independent of each other.
-Referring to Scenario 6-2, the probability is 0.25 that John's income as a waiter is no more than how much in a given month?
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SCENARIO 6-5
Ball bearings are manufactured with a mean diameter of 6 millimeters (mm).Because of the inherent manufacturing process variability, the lots of bearings are approximately normally distributed with a standard deviation of 0.03 mm.
-Using Scenario 6-5, if there is an order for 60,000 ball bearings and it states the bearing diameters must be between 5.96 and 6.04 mm, how many should the manager manufacture?
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The amount of time necessary for assembly line workers to complete a product is a normal variable with a mean of 15 minutes and a standard deviation of 2 minutes.The probability isthat a product is assembled in less than 12 minutes.
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