Exam 1: The Foundations: Logic and Proofs

arrow
  • Select Tags
search iconSearch Question
  • Select Tags

P(x, y) means x+2y=xy"“ x + 2 y = x y " where x and y are integers. Determine the truth value of the statement. - xyP(x,y)\forall x \exists y P ( x , y )

(True/False)
4.7/5
(45)

Match the statement in symbols with one of the English statements in this list: 1. Some freshmen are math majors. 2. Every math major is a freshman. 3. No math major is a freshman. - x(¬(M(x)¬F(x)))\forall x ( \neg ( M ( x ) \wedge \neg F ( x ) ) )

(Short Answer)
4.8/5
(32)

suppose that Q(x) is “ x+1=2x"Q ( x ) \text { is “ } x + 1 = 2 x " \text {, } where x is a real number. Find the truth value of the statement. - Q(2)Q ( 2 )

(True/False)
4.9/5
(32)

In questions , determine whether the proposition is TRUE or FALSE. -If 1 < 0, then 3 = 4.

(True/False)
4.9/5
(33)

Show that the premises "Jean is a student in my class" and "No student in my class is from England" imply the conclusion "Jean is not from England".

(Short Answer)
4.9/5
(40)

I will go to the play or read a book, but not both.

(Short Answer)
4.8/5
(34)

suppose the variables x and y represent real numbers, and L(x,y):x If x<y, then x is not equal to y\text { If } x < y \text {, then } x \text { is not equal to } y \text {. }

(Short Answer)
5.0/5
(43)

suppose the variables x and y represent real numbers, and L(x,y):x0 P(x):x is a prime number. Write the statement in good English without using any variables in your answer. - xyL(x,y)\forall x \exists y \quad L ( x , y )

(Short Answer)
4.7/5
(31)

Prove that (q(p¬q))¬p( q \wedge ( p \rightarrow \neg q ) ) \rightarrow \neg p is a tautology using propositional equivalence and the laws of logic.

(Short Answer)
4.9/5
(33)

Match the statement in symbols with one of the English statements in this list: 1. Some freshmen are math majors. 2. Every math major is a freshman. 3. No math major is a freshman. - x(M(x)¬F(x))\forall x ( M ( x ) \rightarrow \neg F ( x ) )

(Short Answer)
4.8/5
(28)

Consider the following theorem: If x is an odd integer, then x + 2 is odd. Give a proof by contradiction of this theorem.

(Short Answer)
4.9/5
(36)

suppose the variable x represents people, and F(x):x is friendly T(x):x is tall A(x):x is angry. F ( x ) : x \text { is friendly } \quad T ( x ) : x \text { is tall } \quad A ( x ) : x \text { is angry. } Write the statement using these predicates and any needed quantifiers. -If a person is friendly, then that person is not angry.

(Short Answer)
4.8/5
(41)

Write the contrapositive, converse, and inverse of the following: If you try hard, then you will win.

(Short Answer)
4.7/5
(30)

Find a proposition with three variables p, q, and r that is true when p and r are true and q is false, and false otherwise.

(Short Answer)
4.8/5
(41)

In questions , determine whether the proposition is TRUE or FALSE. -If 1 + 1 = 2 or 1 + 1 = 3, then 2 + 2 = 3 and 2 + 2 = 4.

(True/False)
4.8/5
(30)

P(x, y) means x+2y=xy"“ x + 2 y = x y " where x and y are integers. Determine the truth value of the statement. - yxP(x,y)\exists y \forall x P ( x , y )

(True/False)
4.9/5
(38)

Find a proposition using only p,q,¬p , q , \neg , and the connective \vee with the truth table at the right. p q ?

(Short Answer)
4.9/5
(32)

Construct a combinatorial circuit using inverters, OR gates, and AND gates, that produces the outputs in from input bits p, q and r. - (¬p¬q)(p¬r)( \neg p \wedge \neg q ) \vee ( p \wedge \neg r )

(Short Answer)
4.7/5
(43)

Determine whether p(qr) and p(qr) are equivalent. p \rightarrow ( q \rightarrow r ) \text { and } p \rightarrow ( q \wedge r ) \text { are equivalent. }

(Short Answer)
4.8/5
(36)

Explain why an argument of the following form is not valid: p\rightarrowq \negp \therefore\negq

(Short Answer)
4.8/5
(30)
Showing 101 - 120 of 200
close modal

Filters

  • Essay(0)
  • Multiple Choice(0)
  • Short Answer(0)
  • True False(0)
  • Matching(0)