Exam 12: Boolean Algebra

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Write x + z as a sum-of-products in the variables x, y, and z.

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Show that the Boolean function F given by F(x,y,z)=xˉ+y+xy+x+yF ( x , y , z ) = \overline { \bar { x } + y } + x y + \overline { x + y } simplifies to x+yˉx + \bar { y } by using only the definition of a Boolean algebra.

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In questions mark each statement TRUE or FALSE. -  There are n2 minterms in the variables x1,x2,,xn\text { There are } n ^ { 2 } \text { minterms in the variables } x _ { 1 } , x _ { 2 } , \ldots , x _ { n } \text {. }

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In questions determine whether the statement is TRUE or FALSE. Assume that x, y, and z represent Boolean variables. -x + x y + x = x.

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Procomplemenve that thetation,setandof realthenurealmbners,umwithbers 0additionand 1 aands them0ultiplicationand the 1 respof realectivnelyum, bisersnotasa+Boandolean· , negationalgebra. as

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Write xy+xyzˉx y + x y \bar { z } as a sum-of-products in the variables x,y, and zx , y , \text { and } z

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In questions mark each statement TRUE or FALSE. - x+y=xˉyˉx + y = \bar { x } \mid \bar { y }

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If f(w,x,y,z)=(xˉ+yzˉ)+(wˉx)f ( w , x , y , z ) = \overline { ( \bar { x } + y \bar { z } ) } + ( \bar { w } x ) find f(1,1,0,0)f ( 1,1,0,0 )

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Construct a circuit using inverters, OR gates, and AND gates that gives an output of 1 if and only if three people on a committee do not all vote the same.

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In questions determine whether the statement is TRUE or FALSE. Assume that x, y, and z represent Boolean variables. -(x x + 1) = (x + 1)(x + 1).

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In questions mark each statement TRUE or FALSE. -  If f(z,y,z)=xyz, then f(z,y,z)=xˉyˉzˉ\text { If } f ( z , y , z ) = x y z \text {, then } \overline { f ( z , y , z ) } = \bar { x } \bar { y } \bar { z } \text {. }

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Using only the five properties associative laws, commutative laws, distributive laws, identity laws, and complement laws, prove that x+1=1x + 1 = 1 is true in all Boolean algebras.

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Let F(x,y,z)=(yˉz)(x+xˉy)F ( x , y , z ) = \overline { ( \bar { y } z ) } ( x + \bar { x } y ) . Draw a logic gate diagram for F .

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If f(w,x,y,z)=(xˉ+yzˉ)+(wˉx)f ( w , x , y , z ) = ( \overline{\bar { x } + y \bar { z }} ) + ( \bar { w } x ) , find f(1,1,1,1)f ( 1,1,1,1 )

(Short Answer)
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In questions determine whether the statement is TRUE or FALSE. Assume that x, y, and z represent Boolean variables. - yz+xˉ=yzx\overline { y z + \bar { x } } = \overline { y z } x

(True/False)
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In questions mark each statement TRUE or FALSE. -  When written as a sum of minterms in the variables x and y,1=xy+xyˉ+xˉy+xˉyˉ\text { When written as a sum of minterms in the variables } x \text { and } y , 1 = x y + x \bar { y } + \bar { x } y + \bar { x } \bar { y } \text {. }

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Find the sum-of-products expansion of the Boolean function f(x, y, z) that is 1 if and only if exactly two of the three variables have value 1.

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