Exam 5: Exponential and Logarithmic Functions

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Graph the function. - f(x)=3exf(x)=3 e^{-x}  Graph the function. - f(x)=3 e^{-x}

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Match the equation with its graph. - y=2xy = 2 ^ { - x }

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The number of quarters needed to double an investment when a lump sum is invested at 10%, compounded quarterly, is given b n=ln2ln1.025\mathrm { n } = \frac { \ln 2 } { \ln 1.025 } Find n, rounded to the nearest tenth.

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Graph the function. - f(x)=2xf(x)=2^{x}  Graph the function. - f(x)=2^{x}

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Provide an appropriate response. -If interest is compounded monthly at 5% per year for 14 years, explain how to find the number of compounding periods and the interest rate per compounding period.

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The decay of 514 mg of an isotope is given by A( A(t)=514e0.021tA ( t ) = 514 e ^ { - 0.021 t } , where t is time in years. Find the amount left after 63 years.

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Use a change of base formula to evaluate the given logarithm. Approximate to three decimal places. -ln (5 x-2)=ln 12-ln (x-6)

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Find the function value. -Let f(x)=(16)xf ( x ) = \left( \frac { 1 } { 6 } \right) ^ { x } . Find f(3)f ( 3 ) .

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Find the inverse of the function. - f(x)=ex+2f ( x ) = e ^ { - x } + 2

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Provide an appropriate response. -The following table has the inputs, x, and the outputs for three functions, f, g, and h. Test the percent change of the outputs to determine which function is exactly exponential, which is approximately exponential, and which is not exponential. () () () 0 1 1.5 7 1 2 2.25 8 2 4 4 9 3 8 5 10 4 16 7.75 11 5 32 12 12

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Find the value of the logarithm without using a calculator. -log8 32

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Graph the function - f(x)=lnx4f(x)=\ln x-4  Graph the function - f(x)=\ln x-4

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An earthquake was recorded which was 2,511,886 times more powerful than a reference level zero earthquake. What is the magnitude of this earthquake on the Richter scale? Intensity on the Richter scale is lo log(II)\log \left( \frac { \mathrm { I } } { \mathrm { I } } \right)

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Graph the function. - f(x)=e3x3f ( x ) = e ^ { 3 x } - 3  Graph the function. - f ( x ) = e ^ { 3 x } - 3

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Rewrite as a single logarithm. - 2logbm45logbn+16logbj4logbk2 \log _ { b } m - \frac { 4 } { 5 } \log _ { b } n + \frac { 1 } { 6 } \log _ { b } j - 4 \log _ { b } k

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Barbara knows that she will need to buy a new car in 2 years. The car will cost $15,000 by then. How much should she invest now at 8%, compounded quarterly, so that she will have enough to buy a new car?

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Evaluate. Round dollar amounts to the nearest cent and other answers to the nearest thousandth when necessary. - 1,000(1+rk)kn for n=7,r=5%,k=21,000 \left( 1 + \frac { \mathrm { r } } { \mathrm { k } } \right) ^ { \mathrm { kn } } \text { for } \mathrm { n } = 7 , \mathrm { r } = 5 \% , \mathrm { k } = 2

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The number of quarters needed to double an investment when a lump sum is invested at 10%, compounded quarterly, is given b n=log1.0252n = \log 1.025^2 2. Use the change of base formula to find n, rounded to the nearest tenth.

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In September 1998 the population of the country of West Goma in millions was modeled by f(x)=17.5e0.0010xf ( x ) = 17.5 e ^ { 0.0010 x } . At the same time the population of East Goma in millions was modeled by g(x)=13.7e0.0129x\mathrm { g } ( \mathrm { x } ) = 13.7 \mathrm { e } 0.0129 \mathrm { x } . In both formulas xx is the year, where x=0x = 0 corresponds to September 1998 . Assuming these trends continue, estimate the year when the population of West Goma will equal the population of East Goma.

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Write the logarithmic equation in exponential form. - lnx=7\ln x = - 7

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