Exam 8: Hypothesis Testing

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Alyson Silvastein, a scientist, reports that the average number of hours a person can go without sleep and still function normally is 29 with a standard deviation of five hours. A sample of 49 people had an average of 31 hours that they could go without sleep and still function normally. The test value for this hypothesis would be 2.8.

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The following display from a TI-84 Plus calculator presents the results of a hypothesis test for a population mean μ\mu .  The following display from a TI-84 Plus calculator presents the results of a hypothesis test for a population mean  \mu .    Do you reject  H _ { 0 }  at the  \alpha = 0.10  level of significance? Do you reject H0H _ { 0 } at the α=0.10\alpha = 0.10 level of significance?

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A recent survey of gasoline prices indicated that the national average was $4.098\$ 4.098 per gallon. The Dallas Automobile Club claimed that gasoline in Texas was significantly lower than the national average. A survey covering 10 different suburbs in Dallas found the average price of gasoline to be $3.924\$ 3.924 per gallon with a population standard deviation of $0.053\$ 0.053 . What critical value should be used to test the claim using α=0.01\alpha = 0.01 ?

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It has been claimed that at UCLA at least 40%40 \% of the students live on campus. In a random sample of 250 students, 90 were found to live on campus. Does the evidence support the claim at α=0.01\alpha = 0.01 ?

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A sample of 46 students enroll in a program that claims to improve scores on the quantita reasoning portion of the Graduate Record Examination (GRE). The participants take a mc GRE test before the program begins and again at the end to measure their improvement. The mean number of points improved was xˉ=16\bar { x } = 16 . Assume the standard deviation is σ=53\sigma = 53 and let μ\mu be the population mean number of points improved. To determine whether the program is effective, a test is made of the hypotheses H0:μ=0H _ { 0 } : \mu = 0 versus H1:μ>0H _ { 1 } : \mu > 0 . ive Compute the value of the test statistic.

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In a simple random sample of size 88 , there were 22 individuals in the category of interest. It is desired to test H0:p=0.31H _ { 0 } : p = 0.31 versus H1:p<0.31H _ { 1 } : p < 0.31 . Compute the test statistic zz

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The mean annual tuition and fees for a sample of 11 private colleges was $26,500 with a standard deviation of $6000. A dotplot shows that it is reasonable to assume that the population is approximately normal. You wish to test whether the mean tuition and fees for private colleges is different from $31,000. i). State the null and alternate hypotheses. ii). Compute the value of the test statistic and state the number of degrees of freed iii). State a conclusion regarding H0H _ { 0 } . Use the α=0.05\alpha = 0.05 level of significance. .

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A test is made of H0:μ=60H _ { 0 } : \mu = 60 versus H1:μ>60H _ { 1 } : \mu > 60 . A sample of size n=77n = 77 is drawn, and xˉ=64\bar { x } = 64 . The population standard deviation is σ=23\sigma = 23 . Compute the value of the test statistic zz and determine if H0H _ { 0 } is rejected at the α=0.05\alpha = 0.05 level.

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Which type of null hypothesis is used in the figure below? Which type of null hypothesis is used in the figure below?

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A test of H0:μ=49H _ { 0 } : \mu = 49 versus H1:μ<49H _ { 1 } : \mu < 49 is performed using a significance level of α=0.05\alpha = 0.05 . The value of the test statistic is z=1.70z = - 1.70 . If the true value of μ\mu is 45 does the conclusion result in a Type I error, a Type II error, or ह correct decision?

(Multiple Choice)
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The following display from a TI-84 Plus calculator presents the results of a hypothesis tes The following display from a TI-84 Plus calculator presents the results of a hypothesis tes    What are the null and alternate hypotheses? What are the null and alternate hypotheses?

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Thirty-seven members of a bowling league sign up for a program that claims to in bowling scores. The participants bowl a set of five games before the program begi a set of five games again at the end to measure their improvement. The mean number of points improved (over the set of five games) was xˉ=22\bar { x } = 22 . Ass the standard deviation is σ=44\sigma = 44 and let μ\mu be the population mean number of points improved for the set of five games. To determine whether the program is effective, a test is made of the hypotheses H0:μ=0H _ { 0 } : \mu = 0 versus H1:μ>0H _ { 1 } : \mu > 0 . i). Compute the value of the test statistic. ii). Compute the PP -value. iii). Do you reject H0H _ { 0 } at the α=0.01\alpha = 0.01 level? ove

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 Using the z table, determine the critical value for the right-tailed test with α=0.035\text { Using the } z \text { table, determine the critical value for the right-tailed test with } \alpha = 0.035 \text {. }

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Nationwide, the average waiting time until a electric utility customer service representative answers a call is 310 seconds. The Gigantic Kilowatt Energy Company Randomly sampled 40 calls and found that, on average, they were answered in 287 Seconds with a population standard deviation of 30 seconds. Can the company claim that They are faster than the average utility at α = 0.05?

(Multiple Choice)
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The Energy Information Administration reported that 51.5%51.5 \% of homes in the United States were heated by natural gas. A random sample of 200 homes found that 111 heated by natural gas. Does the evidence support the claim or has the percentage changed? Use α=0.05\alpha = 0.05 and the PP -value method.

(Multiple Choice)
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A test of H0:μ=65H _ { 0 } : \mu = 65 versus H1:μ<65H _ { 1 } : \mu < 65 is performed using a significance level of α=0.05\alpha = 0.05 . The PP -value is 0.0550.055 . If the true value of μ\mu is 65 , does the conclusion result in a Type I error, a Type II error, or correct decision?

(Multiple Choice)
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The average greyhound can reach a top speed of 18.818.8 meters per second. A particular greyhound breeder claims her dogs are faster than the average greyhound. A sample of 50 of her dogs ran, on average, 19.219.2 meters per second with a population standard deviation of 1.41.4 meters per second. With α=0.05\alpha = 0.05 , is her claim correct?

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Assume that a 95%95 \% confidence interval for the mean is 15.0<μ<17.015.0 < \mu < 17.0 . The null hypothesis H0:μ=14.0H _ { 0 } : \mu = 14.0 at α=0.05\alpha = 0.05 would

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 Using the z table, determine the critical value for the left-tailed test with α=0.02\text { Using the } z \text { table, determine the critical value for the left-tailed test with } \alpha = 0.02 \text {. }

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The following output from MINITAB presents the results of a hypothesis test for a population mean μ\mu . Test of mu=46vs.\mathrm { mu } = 46 \mathrm { vs } . not =46= 46 Mean StDev SE Mean 95\% CI P 65 43.40 7.941089 0.984971 (41.432298,45.367702) -2.639672 0.0104 What is the value of xˉ\bar { x } ?

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