Exam 2: More on Functions

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Determine if the graph is symmetric with respect to x-axis, y-axis, and/or the origin. -Determine if the graph is symmetric with respect to x-axis, y-axis, and/or the origin. -

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Determine the intervals on which the function is increasing, decreasing, and constant. -Determine the intervals on which the function is increasing, decreasing, and constant. -  A) Increasing on  (-2,0)  and  (3,4) ; Decreasing on  (-5,-2)  and  (1,3)  B) Increasing on  (-2,0)  and  (3,5) ; Decreasing on  (1,3) ; Constant on  (-5,-2)  C) Increasing on  (-1,0)  and  (3,5) ; Decreasing on  (0,3) ; Constant on  (-5,-3)  D) Increasing on  (1,3) ; Decreasing on  (-2,0)  and  (3,5) ; Constant on  (2,5) A) Increasing on (-2,0) and (3,4) ; Decreasing on (-5,-2) and (1,3) B) Increasing on (-2,0) and (3,5) ; Decreasing on (1,3) ; Constant on (-5,-2) C) Increasing on (-1,0) and (3,5) ; Decreasing on (0,3) ; Constant on (-5,-3) D) Increasing on (1,3) ; Decreasing on (-2,0) and (3,5) ; Constant on (2,5)

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The given point is on the graph of y = f(x). Find a point on the graph of y = g(x). -g(x) = f(-4x); (5, -4)

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Find f(x) and g(x) such that h(x) = =(fg)(x)= ( f \circ g ) ( x ) - h(x)=x+2x1h ( x ) = \sqrt { \frac { x + 2 } { x - 1 } } A) f(x)=x+2x1,g(x)=xf ( x ) = \frac { x + 2 } { x - 1 } , g ( x ) = \sqrt { x } B) f(x)=1x1,g(x)=x+2f ( x ) = \sqrt { \frac { 1 } { x - 1 } } , g ( x ) = x + 2 C) f(x)=x+2,g(x)=1x1f ( x ) = \sqrt { x + 2 } , g ( x ) = \frac { 1 } { x - 1 } D) f(x)=x,g(x)=x+2x1f ( x ) = \sqrt { x } , g ( x ) = \frac { x + 2 } { x - 1 }

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Answer the question. -How can the graph of f(x)=0.4(x+7)29f ( x ) = 0.4 ( x + 7 ) ^ { 2 } - 9 be obtained from the graph of y=x2?y = x ^ { 2 } ?

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Write an equation for the piecewise function. -Write an equation for the piecewise function. -

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The graph of the function f is shown below. Match the function g with the correct graph. -g(x)= -f(-x)-3 The graph of the function f is shown below. Match the function g with the correct graph. -g(x)= -f(-x)-3

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Find the requested function value. -Find the requested function value. -  Find  Find Find the requested function value. -  Find

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Determine algebraically whether the function is even, odd, or neither even nor odd. -Determine algebraically whether the function is even, odd, or neither even nor odd. -

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The graph of the function f is shown below. Match the function g with the correct graph. -g(x)= f(x+2) The graph of the function f is shown below. Match the function g with the correct graph. -g(x)= f(x+2)

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Graph the equation. -Graph the equation. -  A)    B)   C)   D)  A) Graph the equation. -  A)    B)   C)   D)  B) Graph the equation. -  A)    B)   C)   D)  C) Graph the equation. -  A)    B)   C)   D)  D) Graph the equation. -  A)    B)   C)   D)

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For the pair of functions, find the indicated domain. - f(x)=2x5,g(x)=x+10f ( x ) = 2 x - 5 , g ( x ) = \sqrt { x + 10 } Find the domain of f+g

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Solve the problem. -The weight that a horizontal beam can support varies inversely as the length of the beam. Suppose that a 2-m beam can support 560kg . How many kilograms can a 2-m beam support?

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Graph the function. -Graph the function. -

(Multiple Choice)
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Find f(x) and g(x) such that h(x) = (f g)(x). - h(x)=(x3+55x3)8h ( x ) = \left( \frac { x ^ { 3 } + 5 } { 5 - x ^ { 3 } } \right) ^ { 8 }

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For the pair of functions, find the indicated sum, difference, product, or quotient. - f(x)=x21,g(x)=9x+1f ( x ) = x ^ { 2 } - 1 , g ( x ) = 9 x + 1 Find (f/g)(19)( f / g ) \left( - \frac { 1 } { 9 } \right)

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For the pair of functions, find the indicated domain. -f(x)=2 x-5, g(x)=x+5g ( x ) = \sqrt { x + 5 } Find the domain of  g of. \text { g of. } A) [,0)[ - \infty , 0 ) B) [5,)[ 5 , \infty ) C) [0,)[ 0 , \infty ) D) (-5,5)

(Short Answer)
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Write an equation for the piecewise function. - Write an equation for the piecewise function. -  A)  f ( x ) = \left\{ \begin{array} { l l }  2 x - 3 , & \text { for } x \neq 3 \\ - 3 , & \text { for } x = 3 \end{array} \right.  B)  f ( x ) = \left\{ \begin{array} { l l }  x - 3 , & \text { for } x \neq 3 \\ - 2 , & \text { for } x = 3 \end{array} \right.  C)  f ( x ) = \left\{ \begin{array} { l l }  2 x - 3 , & \text { for } x \neq 3 \\ - 2 , & \text { for } x = 3 \end{array} \right.  D)  f ( x ) = \left\{ \begin{array} { l l }  2 x - 3 , & \text { for } x < 3 \\ 2 x + 3 , & \text { for } x \geq 3 \end{array} \right. A) f(x)={2x3, for x33, for x=3f ( x ) = \left\{ \begin{array} { l l } 2 x - 3 , & \text { for } x \neq 3 \\- 3 , & \text { for } x = 3\end{array} \right. B) f(x)={x3, for x32, for x=3f ( x ) = \left\{ \begin{array} { l l } x - 3 , & \text { for } x \neq 3 \\- 2 , & \text { for } x = 3\end{array} \right. C) f(x)={2x3, for x32, for x=3f ( x ) = \left\{ \begin{array} { l l } 2 x - 3 , & \text { for } x \neq 3 \\- 2 , & \text { for } x = 3\end{array} \right. D) f(x)={2x3, for x<32x+3, for x3f ( x ) = \left\{ \begin{array} { l l } 2 x - 3 , & \text { for } x < 3 \\2 x + 3 , & \text { for } x \geq 3\end{array} \right.

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Determine whether the given function is even, odd, or neither even nor odd. -Determine whether the given function is even, odd, or neither even nor odd. -  A) Neither B) Odd C) Even A) Neither B) Odd C) Even

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For the function f, construct and simplify the difference quotient f(x+h)f(x)h\frac { f ( x + h ) - f ( x ) } { h } - f(x)=15xf ( x ) = \frac { 1 } { 5 x } A) 1x(x+h)\frac { - 1 } { x ( x + h ) } B) 15×(x+h)\frac { - 1 } { 5 \times ( x + h ) } C) 15x\frac { 1 } { 5 x } D) 0

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