Exam 6: The Normal Distribution and Other Continuous Distributions
Exam 1: Introduction145 Questions
Exam 2: Organizing and Visualizing Data210 Questions
Exam 3: Numerical Descriptive Measures153 Questions
Exam 4: Basic Probability171 Questions
Exam 5: Discrete Probability Distributions218 Questions
Exam 6: The Normal Distribution and Other Continuous Distributions191 Questions
Exam 7: Sampling and Sampling Distributions197 Questions
Exam 8: Confidence Interval Estimation196 Questions
Exam 9: Fundamentals of Hypothesis Testing: One-Sample Tests165 Questions
Exam 10: Two-Sample Tests210 Questions
Exam 11: Analysis of Variance213 Questions
Exam 12: Chi-Square Tests and Nonparametric Tests201 Questions
Exam 13: Simple Linear Regression213 Questions
Exam 14: Introduction to Multiple Regression355 Questions
Exam 15: Multiple Regression Model Building96 Questions
Exam 16: Time-Series Forecasting168 Questions
Exam 17: Statistical Applications in Quality Management133 Questions
Exam 18: A Roadmap for Analyzing Data54 Questions
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The amount of time between successive TV watching by first graders follows an exponential distribution with a mean of 10 hours. The probability that a given first grader spends between 10 and 15 hours between successive TV watching is ________.
(Short Answer)
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TABLE 6-2
John has two jobs. For daytime work at a jewelry store he is paid $15,000 per month, plus a commission. His monthly commission is normally distributed with mean $10,000 and standard deviation $2,000. At night he works as a waiter, for which his monthly income is normally distributed with mean $1,000 and standard deviation $300. John's income levels from these two sources are independent of each other.
-Referring to Table 6-2, John's commission from the jewelry store will be between what two values symmetrically distributed around the population mean 80% of the time?
(Short Answer)
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The amount of tea leaves in a can from a particular production line is normally distributed with μ = 110 grams and σ = 25 grams. Approximately 83% of the can will have at least how many grams of tea leaves?
(Essay)
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TABLE 6-6
According to Investment Digest, the arithmetic mean of the annual return for common stocks from 1926-2010 was 9.5% but the value of the variance was not mentioned. Also 25% of the annual returns were below 8% while 65% of the annual returns were between 8% and 11.5%. The article claimed that the distribution of annual return for common stocks was bell-shaped and approximately symmetric. Assume that this distribution is normal with the mean given above. Answer the following questions without the help of a calculator, statistical software or statistical table.
-Referring to Table 6-6, what is the value above which will account for the highest 25% of the possible annual returns?
(Short Answer)
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You were told that the amount of time lapsed between consecutive trades on the New York Stock Exchange followed a normal distribution with a mean of 15 seconds. You were also told that the probability that the time lapsed between two consecutive trades to fall between 16 to 17 seconds was 13%. The probability that the time lapsed between two consecutive trades would fall below 13 seconds was 7%. What is the probability that the time lapsed between two consecutive trades will be between 14 and 15 seconds?
(Short Answer)
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TABLE 6-2
John has two jobs. For daytime work at a jewelry store he is paid $15,000 per month, plus a commission. His monthly commission is normally distributed with mean $10,000 and standard deviation $2,000. At night he works as a waiter, for which his monthly income is normally distributed with mean $1,000 and standard deviation $300. John's income levels from these two sources are independent of each other.
-Referring to Table 6-2, for a given month, what is the probability that John's commission from the jewelry store is between $11,000 and $12,000?
(Short Answer)
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TABLE 6-5
A company producing orange juice buys all its oranges from a large orange orchard. The amount of juice that can be squeezed from each of these oranges is approximately normally distributed with a mean of 4.7 ounces and some unknown standard deviation. The company's production manager knows that the probability is 30.85% that a randomly selected orange will contain less than 4.5 ounces of juice. Also the probability is 10.56% that a randomly selected orange will contain more than 5.2 ounces of juice. Answer the following questions without the help of a calculator, statistical software or statistical table.
-Referring to Table 6-5, what is the probability that a randomly selected orange will contain between 4.2 and 4.9 ounces of juices?
(Short Answer)
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The amount of time necessary for assembly line workers to complete a product is a normal random variable with a mean of 15 minutes and a standard deviation of 2 minutes. So, 17% of the products would be assembled within ________ minutes.
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Suppose Z has a standard normal distribution with a mean of 0 and standard deviation of 1. The probability that Z is between -2.33 and 2.33 is ________.
(Short Answer)
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Suppose the light bulbs in a factory burn out at a rate of 50 bulbs per month. Which of the following distributions would you use to determine the probability that the next two light bulbs will burn out 2 days apart?
(Multiple Choice)
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TABLE 6-2
John has two jobs. For daytime work at a jewelry store he is paid $15,000 per month, plus a commission. His monthly commission is normally distributed with mean $10,000 and standard deviation $2,000. At night he works as a waiter, for which his monthly income is normally distributed with mean $1,000 and standard deviation $300. John's income levels from these two sources are independent of each other.
-Referring to Table 6-2, for a given month, what is the probability that John's commission from the jewelry store is less than $13,000?
(Short Answer)
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