Exam 10: Topics From Analytical Geometry

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Find a polar equation in r and θ\theta that has the same graph as the equation in x and y. x=6x = - 6

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Find a polar equation of the conic with focus at the pole that has the eccentricity and equation of directrix. e=4,r=2cscθe = 4 , \quad r = - 2 \csc \theta

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An arch of a bridge is semi-elliptical, with major axis horizontal. The base of the arch is 30 feet across, and the highest part of the arch is 10 feet above the horizontal roadway, as shown in the figure. Find the height of the arch 7 feet from the center of the base. An arch of a bridge is semi-elliptical, with major axis horizontal. The base of the arch is 30 feet across, and the highest part of the arch is 10 feet above the horizontal roadway, as shown in the figure. Find the height of the arch 7 feet from the center of the base.

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Find an equation for the ellipse that has its center at the origin and satisfies the conditions.  vertices V(±7,0), foci F(±3,0)\text { vertices } V ( \pm 7,0 ) \text {, foci } F ( \pm 3,0 )

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Find a polar equation in r and θ\theta that has the same graph as the equation in x and y. (x8)2+y2=64( x - 8 ) ^ { 2 } + y ^ { 2 } = 64

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Find the foci of the ellipse. x249+y29=1\frac { x ^ { 2 } } { 49 } + \frac { y ^ { 2 } } { 9 } = 1

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Find an equation in x and y for the polar equation. r=1412+4sinθr = \frac { 14 } { 12 + 4 \sin \theta }

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Find a polar equation in r and θ\theta that has the same graph as the equation in x and y. 3y=x3 y = - x

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Polar equations of conics can be used to describe the motion of comets. These paths can be graphed using the following polar equation, where e is the eccentricity of the conic and r per is the perihelion distance measured in AU. For Encke's Comet r per = 0.3317 and e = 0.8499, determine whether its trajectory is elliptical, parabolic, or hyperbolic. r=rper(1+e)1ecosθr = \frac { r _ { \mathrm { per } } ( 1 + e ) } { 1 - e \cos \theta }

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Find an equation of the parabola that satisfies the condition. Vertex V(4,0)V ( - 4,0 ) , focus F(2,0)F ( - 2,0 )

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Find an equation for the parabola that has a horizontal axis and passes through the given points. P(34,2),Q(34,5),R(2,2)P ( 34 , - 2 ) , Q ( 34,5 ) , R ( - 2,2 )

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Find the foci of the ellipse. (x+1)225+(y2)24=1\frac { ( x + 1 ) ^ { 2 } } { 25 } + \frac { ( y - 2 ) ^ { 2 } } { 4 } = 1

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Find the eccentricity. r=cscθ(cscθ+cotθ)r = \csc \theta ( \csc \theta + \cot \theta )

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Classify the conic. r=622sinθr = \frac { 6 } { 2 - 2 \sin \theta }

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Sketch the graph of the ellipse, showing the foci . 4x2+y2=6y84 x ^ { 2 } + y ^ { 2 } = 6 y - 8

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Find a polar equation of the conic with focus at the pole that has the eccentricity and equation of directrix. e=1e = 1 , rcosθ=7r \cos \theta = 7

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Find a polar equation in r and 0 of the parabola with focus at the pole and the given vertex. V(9,π2)V \left( 9 , \frac { \pi } { 2 } \right)

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Find a polar equation in r and 0 of the parabola with focus at the pole and the given vertex. V(5,0)V ( 5,0 )

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Shown in the figure is the Lissajous figure given by x=4sin3t,y=4sin1.5t;t0x = 4 \sin 3 t , y = 4 \sin 1.5 t ; t \geq 0 Find the period of the figure - that is, the length of the smallest t-interval that traces the curve.  Shown in the figure is the Lissajous figure given by  x = 4 \sin 3 t , y = 4 \sin 1.5 t ; t \geq 0  Find the period of the figure - that is, the length of the smallest t-interval that traces the curve.

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Lissajous figures are used in the study of electrical circuits to determine the phase difference φ\varphi between a known voltage V1(t)=Asin(at)V _ { 1 } ( t ) = A \sin ( a t ) and an unknown voltage V2(t)=Bsin(ωt+φ)V _ { 2 } ( t ) = B \sin ( ω t + \varphi ) adta \mathrm{dt} having the same frequency. The voltages are graphed parametrically as x=V1(t)x = V _ { 1 } ( t ) and y=V2(t)y = V _ { 2 } ( t ) . If φ\varphi is acute, then φ=sin1yintymax\varphi = \sin ^ { - 1 } \frac { y _ { \mathrm { int } } } { y _ { \max } } where y int is the nonnegative y -intercept and y max is the maximum y -value on the curve. Graph the parametric curve and use the graph to approximate φ\varphi in degrees if (t)=40(60\pit),(t)=90(60\pit-\pi/3), 0\leqt\leq0.035

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