Exam 25: Capacitance

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A parallel-plate capacitor, with air dielectric, is charged by a battery, after which the battery is disconnected. A slab of glass dielectric is then slowly inserted between the plates. As it is being inserted:

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B

A 20-F capacitor is charged to 200 V. Its stored energy is:

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C

A battery is used to charge a parallel-plate capacitor, after which it is disconnected. Then the plates are pulled apart to twice their original separation. This process will double the:

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C

Two conducting spheres have radii of R1 and R2 with R1 greater than R2. If they are far apart the capacitance is proportional to:

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A capacitor C "has a charge Q". The actual charges on its plates are:

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Two identical capacitors, each with capacitance C, are connected in parallel and the combination is connected in series to a third identical capacitor. The equivalent capacitance of this arrangement is:

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Let Q denote charge, V denote potential difference and U denote stored energy. Of these quantities, capacitors in series must have the same:

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A 2- μ\mu F and a 1- μ\mu F capacitor are connected in series and charged from a battery. They store charges P and Q, respectively. When disconnected and charged separately using the same battery, they have charges R and S, respectively. Then:

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Let Q denote charge, V denote potential difference and U denote stored energy. Of these quantities, capacitors in parallel must have the same:

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Two parallel-plate capacitors with the same plate separation but different capacitance are connected in parallel to a battery. Both capacitors are filled with air. The quantity that is NOT the same for both capacitors when they are fully charged is:

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A charged capacitor stores 10 C at 40 V. Its stored energy is:

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The diagram shows six 6- μ\mu F capacitors. The capacitance between points a and b is:  The diagram shows six 6- \mu F capacitors. The capacitance between points a and b is:

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Each of the four capacitors shown is 500 μ\mu F. The voltmeter reads 1000V. The magnitude of the charge, in coulombs, on each capacitor plate is:  Each of the four capacitors shown is 500  \mu F. The voltmeter reads 1000V. The magnitude of the charge, in coulombs, on each capacitor plate is:

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The capacitance of a parallel-plate capacitor can be increased by:

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A dielectric slab is slowly inserted between the plates of a parallel plate capacitor, while the potential difference between the plates is held constant by a battery. As it is being inserted:

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The plate areas and plate separations of five parallel plate capacitors are The plate areas and plate separations of five parallel plate capacitors are   Rank these according to their capacitances, least to greatest. Rank these according to their capacitances, least to greatest.

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A battery is used to charge a series combination of two identical capacitors. If the potential difference across the battery terminals is V and total charge Q flows through the battery during the charging process then the charge on the positive plate of each capacitor and the potential difference across each capacitor are:

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If the plate area of an isolated charged parallel-plate capacitor is doubled:

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An air-filled parallel-plate capacitor has a capacitance of 1 pF. The plate separation is then doubled and a wax dielectric is inserted, completely filling the space between the plates. As a result, the capacitance becomes 2 pF. The dielectric constant of the wax is:

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A 2- μ\mu F and a 1- μ\mu F capacitor are connected in series and charged by a battery. They store energies P and Q, respectively. When disconnected and charged separately using the same battery, they have energies R and S, respectively. Then:

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