Exam 21: Electric Charge
Exam 1: Measurement31 Questions
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Exam 5: Force and Motion I68 Questions
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Exam 15: Oscillations62 Questions
Exam 16: Waves I71 Questions
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Exam 18: Temperature, Heat, and the First Law of Thermodynamics82 Questions
Exam 19: The Kinetic Theory of Gases95 Questions
Exam 20: Entropy and the Second Law of Thermodynamics56 Questions
Exam 21: Electric Charge45 Questions
Exam 22: Electric Fields49 Questions
Exam 23: Gauss Law34 Questions
Exam 24: Electric Potential44 Questions
Exam 25: Capacitance55 Questions
Exam 26: Current and Resistance49 Questions
Exam 27: Circuits70 Questions
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Exam 30: Induction and Inductance85 Questions
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Exam 35: Interference40 Questions
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Exam 37: Relativity65 Questions
Exam 38: Photons and Matter Waves53 Questions
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Exam 40: All About Atoms76 Questions
Exam 41: Conduction of Electricity in Solids48 Questions
Exam 42: Nuclear Physics67 Questions
Exam 43: Energy From the Nucleus44 Questions
Exam 44: Quarks, Leptons, and the Big Bang52 Questions
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Consider the following procedural steps:
To charge an electroscope by induction, use the sequence:

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B
Charge is distributed uniformly on the surface of a spherical balloon (an insulator). A point particle with charge q is inside. The electrical force on the particle q is greatest when:
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E
When a hard rubber rod is given a negative charge by rubbing it with wool:
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D
A positively charged insulating rod is brought close to an object that is suspended by a string. If the object is repelled away from the rod we can conclude:
(Multiple Choice)
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A particle with charge 2 C charge is placed at the origin, an identical particle, with the same charge, is placed 2 m from the origin on the x axis, and a third identical particle, with the same charge, is placed 2 m from the origin on the y axis. The magnitude of the force on the particle at the origin is:
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A positively charged insulating rod is brought close to an object that is suspended by a string. If the object is attracted toward the rod we can conclude:
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Particles 1, with charge q1 and 2, with a charge q2 are on the x axis, with particle 1 at x = a with and particle 2 at x = -2a. For the net force on a third charged particle, at the origin to be zero q1 and q2 must be related by q2=:
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A positively charged metal sphere A is brought into contact with an uncharged metal sphere B. As a result:
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An electroscope is charged by induction using a glass rod that has been made positive by rubbing it with silk. The electroscope leaves:
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A 5.0-C charge is 10 m from a -2.0-C charge. The electrostatic force is on the positive charge is:
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Two identical conducting spheres A and B carry equal charge. They are separated by a distance much larger than their diameters. A third identical conducting sphere C is uncharged. Sphere C is first touched to A, then to B, and finally removed. As a result, the electrostatic force between A and B, which was originally F, becomes:
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To make an uncharged object have a negative charge we must:
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Two particles have charges Q and -Q (equal magnitude and opposite sign). For a net force of zero to be exerted on a third charge it must be placed:
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A wire contains a steady current of 2 A. The number of electrons that pass a cross section in 2 s is:
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The magnitude of the total negative charge on the electrons in 1 mol of helium (atomic number 2, atomic mass 4) is:
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A negatively charged rubber rod is brought near the knob of a positively charged electroscope. The result is that:
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A charge Q is spread uniformly along the circumference of a circle of radius R. A point particlewith charge q is placed at the center of this circle. The total force exerted on the particle q can be calculated by Coulomb's law:
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A wire contains a steady current of 2 A. The charge that passes a cross section in 2 s is:
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Two protons (p1 and p2) and an electron (e) lie on a straight line, as shown. The directions of the force of p1 on e, the force of p2 on e, and the total force on e, respectively, are: 

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