Exam 3: Vector

Let Then equals:

Let The vector difference is:

If , then:

The angle between and the positive x axis is:

If the x component of a vector , in the xy plane, is half as large as the magnitude of the vector, the tangent of the angle between the vector and the x axis is:

In the diagram, has magnitude 12 and has magnitude 8. The x component of is about:

Let and $\theta$$\neq$ 90 , where $\theta$ is the angle between when they are drawn with their tails at the same point. Which of the following is NOT true?

We say that the displacement of a particle is a vector quantity. Our best justification for this assertion is:

A vector in the xy plane has a magnitude of 25 and an x component of 12. The angle it makes with the positive x axis is:

Let The vector sum is:

If then has magnitude:

Two vectors lie with their tails at the same point. When the angle between them is increased by 20 their scalar product has the same magnitude but changes from positive to negative. The original angle between them was:

Let The angle between these two vectors is given by:

If the magnitude of the sum of two vectors is greater than the magnitude of either vector, then:

Two vectors have magnitudes of 10 and 15. The angle between them when they are drawn with their tails at the same point is 65 . The component of the longer vector along the line perpendicular to the shorter vector, in the plane of the vectors, is:

Two vectors have magnitudes of 10 and 15. The angle between them when they are drawn with their tails at the same point is 65 . The component of the longer vector along the line of the shorter is:

A vector of magnitude 20 is added to a vector of magnitude 25. The magnitude of this sum can be:

Two vectors lie with their tails at the same point. When the angle between them is increased by 20 the magnitude of their vector product doubles. The original angle between them was about:

Vectors lie in the xy plane. We can deduce that if:

The value of is: