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Use the Information Provided to Determine H° for the Following

Question 1

Multiple Choice

Use the information provided to determine Use the information provided to determine H° for the following reaction: H° (kJ ) 3Fe<sub>2</sub>O<sub>3</sub>(s) + CO(g) → 2Fe<sub>3</sub>O<sub>4</sub>(s) + CO<sub>2</sub>(g) H°<sub> </sub>= ? Fe<sub>2</sub>O<sub>3</sub>(s) -824 Fe<sub>3</sub>O<sub>4</sub>(s) -1118 CO(g) -111 CO<sub>2</sub>(g) -394 A) +277 kJ mol<sup>-1</sup> B) -577 kJ mol<sup>-1</sup> C) -47 kJ mol<sup>-1</sup> D) +144 kJ mol<sup>-1</sup> E) -111 kJ mol<sup>-1</sup> H° for the following reaction: Use the information provided to determine H° for the following reaction: H° (kJ ) 3Fe<sub>2</sub>O<sub>3</sub>(s) + CO(g) → 2Fe<sub>3</sub>O<sub>4</sub>(s) + CO<sub>2</sub>(g) H°<sub> </sub>= ? Fe<sub>2</sub>O<sub>3</sub>(s) -824 Fe<sub>3</sub>O<sub>4</sub>(s) -1118 CO(g) -111 CO<sub>2</sub>(g) -394 A) +277 kJ mol<sup>-1</sup> B) -577 kJ mol<sup>-1</sup> C) -47 kJ mol<sup>-1</sup> D) +144 kJ mol<sup>-1</sup> E) -111 kJ mol<sup>-1</sup> H° (kJ Use the information provided to determine H° for the following reaction: H° (kJ ) 3Fe<sub>2</sub>O<sub>3</sub>(s) + CO(g) → 2Fe<sub>3</sub>O<sub>4</sub>(s) + CO<sub>2</sub>(g) H°<sub> </sub>= ? Fe<sub>2</sub>O<sub>3</sub>(s) -824 Fe<sub>3</sub>O<sub>4</sub>(s) -1118 CO(g) -111 CO<sub>2</sub>(g) -394 A) +277 kJ mol<sup>-1</sup> B) -577 kJ mol<sup>-1</sup> C) -47 kJ mol<sup>-1</sup> D) +144 kJ mol<sup>-1</sup> E) -111 kJ mol<sup>-1</sup> ) 3Fe2O3(s) + CO(g) → 2Fe3O4(s) + CO2(g) Use the information provided to determine H° for the following reaction: H° (kJ ) 3Fe<sub>2</sub>O<sub>3</sub>(s) + CO(g) → 2Fe<sub>3</sub>O<sub>4</sub>(s) + CO<sub>2</sub>(g) H°<sub> </sub>= ? Fe<sub>2</sub>O<sub>3</sub>(s) -824 Fe<sub>3</sub>O<sub>4</sub>(s) -1118 CO(g) -111 CO<sub>2</sub>(g) -394 A) +277 kJ mol<sup>-1</sup> B) -577 kJ mol<sup>-1</sup> C) -47 kJ mol<sup>-1</sup> D) +144 kJ mol<sup>-1</sup> E) -111 kJ mol<sup>-1</sup> H° = ? Fe2O3(s) -824
Fe3O4(s) -1118
CO(g) -111
CO2(g) -394


A) +277 kJ mol-1
B) -577 kJ mol-1
C) -47 kJ mol-1
D) +144 kJ mol-1
E) -111 kJ mol-1

Correct Answer:

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