Find the Indefinite Integral by Making the Substitution $x = 6 \tan \theta$

Multiple Choice

Find the indefinite integral by making the substitution
$x = 6 \tan \theta$ $\int x \sqrt { 36 + x ^ { 2 } } d x$

A) $- \frac { 2 \left( x ^ { 2 } + 36 \right) ^ { 3 / 2 } } { 3 } + C$
B) $- \frac { \left( x ^ { 2 } + 36 \right) ^ { 3 / 2 } } { 3 } + C$
C) $\frac { \left( x ^ { 2 } + 36 \right) ^ { 3 / 2 } } { 3 } + C$
D) $\frac { 2 \left( x ^ { 2 } + 36 \right) ^ { 3 / 2 } } { 3 } + C$
E) $\frac { \left( x ^ { 2 } + 36 \right) ^ { 3 / 2 } } { 2 } + C$