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Let F(x,y,z)=z2i+x2j+y2k\mathbf { F } ( x , y , z ) = z ^ { 2 } \mathbf { i } + x ^ { 2 } \mathbf { j } + y ^ { 2 } \mathbf { k }

Question 156

Multiple Choice

Let F(x,y,z) =z2i+x2j+y2k\mathbf { F } ( x , y , z ) = z ^ { 2 } \mathbf { i } + x ^ { 2 } \mathbf { j } + y ^ { 2 } \mathbf { k } and C be the boundary of the surface 4x2y2=z4 - x ^ { 2 } - y ^ { 2 } = z above z = 0. Using Stokes' Theorem, CFTds\int _ { C } \mathbf { F } \cdot \mathbf { T } d s is


A) 3
B) 2
C) 1
D) 0
E) -1

Correct Answer:

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