Let Then F Is

A)Continuous at (2,2)
B)Discontinuous at

Multiple Choice

Let $f ( x , y ) = \left\{ \begin{array} { c c } \frac { x y - 4 } { \sqrt { x y } - 2 } & ( x , y ) \neq ( 2,2 ) \\0 & ( x , y ) = ( 2,2 ) \end{array} \right.$ . Then f is

A) Continuous at (2,2)
B) Discontinuous at (2,2) because f is undefined at (2,2)
C) Discontinuous at (2,2) because the limit of f at (2,2) does not exist
D) Discontinuous at (2,2) because the limit of f at (2,2) is different from the function value at (2,2)
E) Discontinuous at (2,2) for a reason that is different from the ones above