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The Symmetric Equations of the Tangent Line to the Curve z=16x2y2z = 16 - x ^ { 2 } - y ^ { 2 }

Question 26

Multiple Choice

The symmetric equations of the tangent line to the curve of intersection of the surface z=16x2y2z = 16 - x ^ { 2 } - y ^ { 2 } and the plane x = 1 at the point (1, 2, 11) are


A) 2z11=y214,x=12 z - 11 = \frac { y - 2 } { - \frac { 1 } { 4 } } , x = 1
B) 4z11=y214,x=14 z - 11 = \frac { y - 2 } { \frac { 1 } { 4 } } , x = 1
C) 4z11=y214,x=14 z - 11 = \frac { y - 2 } { - \frac { 1 } { 4 } } , x = 1
D) z11=y214,x=1z - 11 = \frac { y - 2 } { \frac { 1 } { 4 } } , x = 1
E) z11=4(y2) ,x=1z - 11 = - 4 ( y - 2 ) , x = 1

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