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The Solution of the Eigenvalue Problem in the Previous Problem λ=((n1/2)π/L)2,X=sin((n1/2)πx/L)\lambda = ( ( n - 1 / 2 ) \pi / L ) ^ { 2 } , X = \sin ( ( n - 1 / 2 ) \pi x / L )

Question 33

Multiple Choice

The solution of the eigenvalue problem in the previous problem is


A) λ=((n1/2) π/L) 2,X=sin((n1/2) πx/L) \lambda = ( ( n - 1 / 2 ) \pi / L ) ^ { 2 } , X = \sin ( ( n - 1 / 2 ) \pi x / L )
B) λ/h=tan(λL) ,X=sin(λx) \sqrt { \lambda } / h = \tan ( \sqrt { \lambda } L ) , X = \sin ( \sqrt { \lambda } x )
C) λ=(nπ/L) 2,X=sin(nπx/L) \lambda = ( n \pi / L ) ^ { 2 } , X = \sin ( n \pi x / L )
D) λ/h=tan(λL) ,X=sin(λx) \sqrt { \lambda } / h = - \tan ( \sqrt { \lambda } L ) , X = \sin ( \sqrt { \lambda } x )
E) λh=tan(λL) ,X=sin(λx) \sqrt { \lambda } h = - \tan ( \sqrt { \lambda } L ) , X = \sin ( \sqrt { \lambda } x )

Correct Answer:

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