Exam 3: Exponential and Logarithmic Functions

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Rewrite the logarithm log4 17 in terms of the natural logarithm.

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Write the logarithmic equation in exponential form. log10010=12\log _ { 100 } 10 = \frac { 1 } { 2 }

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Solve for x. (14)x=64\left( \frac { 1 } { 4 } \right) ^ { x } = 64

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Evaluate the function at the indicated value of x=0.82x = 0.82 .Round your result to three decimal places. f(x)=9lnxf ( x ) = 9 \ln x

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Rewrite the logarithm as a ratio of common logarithms. Log1/7 x

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An initial investment of $2000 grows at an annual interest rate of 4% compounded continuously.How long will it take to double the investment?

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Solve for x.Approximate the result to three decimal places. ex=4e ^ { x } = 4

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Write the exponential equation in logarithmic form. e3x=4e ^ { 3 x } = 4

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Solve the logarithmic equation algebraically.Approximate the result to three decimal places. 8+71lnx=148 + 71 \ln x = 14

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What is the value of the function f(x)=4.8e1.7xf ( x ) = 4.8 e ^ { - 1.7 x } at x=2.5x = 2.5 ? Round to 3 decimal places.

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Use a graphing utility to determine which graph below is the graph of the function. g(x)=0.1e4xg ( x ) = 0.1 e ^ { - 4 x }

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Find the exact value of lne250lne\ln e ^ { 250 } - \ln \sqrt { e } without using a calculator.

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Evaluate the function at the indicated value of x.Round your result to three decimal places. Function Value h(x)=exh ( x ) = e ^ { - x } x=58x = \frac { 5 } { 8 }

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Graph the function. f(x)=3xf ( x ) = 3 ^ { x }

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Use the change-of-base formula to rewrite the logarithm as a ratio of logarithms.Then use a graphing utility to graph the ratio. F(x) = log11.7 x

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Use the properties of logarithms to simplify the expression. log555\log _ { 5 } 5 ^ { 5 }

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Solve for x.Approximate the result to three decimal places. lnx=2\ln x = - 2

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Use a graphing utility to determine which graph below is the graph of the function. s(x)=1.1e(x1)2s ( x ) = 1.1 e ^ { - ( x - 1 ) ^ { 2 } }

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Write the exponential equation in logarithmic form. 811/2=981 ^ { 1 / 2 } = 9

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An initial investment of $5000 doubles in value in 6.3 years.Assuming continuous compounding, what was the interest rate? Round to the nearest tenth of a percent.

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