Question 1

If the expected frequency ei for any cell i is less than 5, we should:

Accepted Answer

A) choose another sample with five or more observations. 
B) use the normal distribution instead of the chi-squared distribution. 
C) combine cells such that each observed frequency fi is 5 or more. 
D) increase the degrees of freedom by 5. 
A) choose another sample with five or more observations. 
B) use the normal distribution instead of the chi-squared distribution. 
C) combine cells such that each observed frequency fi is 5 or more. 
D) increase the degrees of freedom by 5.

Question 2

The number of degrees of freedom for a contingency table with r rows and c columns is:

Accepted Answer

A) r + c 
B) rc 
C) (r - 1)(c -1) 
D) None of these choices. 
A) r + c 
B) rc 
C) (r - 1)(c -1) 
D) None of these choices.

Question 3

A sports preference poll showed the following data for adults and children:
 $$\begin{array}{l}
\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\text { Favorite Sport }\
\begin{array} { | l | c c c c c | } 
\hline \text { gender } & \text { Baseball } & \text { Soccer } & \text { Rugby } & \text { Hockey } & \text { Archery } \
\hline \text { Adults } & 24 & 17 & 30 & 18 & 22 \
\text { Children } & 21 & 20 & 22 & 12 & 28 \
\hline
\end{array}
\end{array}$$ Use the 5% level of significance and test to determine whether sports preferences depend on age group.

Accepted Answer

H₀: Age group and sports preferences are

Question 4

In conducting a chi-squared goodness-of-fit test, an essential condition is that all expected frequencies are at least five.

Accepted Answer

A) True 
 B)False

Question 5

The squared difference between the observed and expected frequencies should be large if there is a significant difference between the proportions.

Accepted Answer

A) True 
 B)False

Question 6

Which statistical technique is appropriate when we wish to analyze the relationship between two qualitative variables with two or more categories?

Accepted Answer

A) The chi-squared test of a multinomial experiment. 
B) The chi-squared test of a contingency table. 
C) The t-test of the difference between two means. 
D) The z-test of the difference between two proportions. 
A) The chi-squared test of a multinomial experiment. 
B) The chi-squared test of a contingency table. 
C) The t-test of the difference between two means. 
D) The z-test of the difference between two proportions.

Question 7

Suppose that two shipping companies, A and B, each decide to estimate the annual percentage of shipments on which a $100 or greater claim for loss or damage was filed by sampling their records, and they report the data shown below. $$\begin{array} { | l | c c | } 
\hline & \text { Company A } & \text { Company B } \
\hline \text { Total shipments sampled } & \text { 800 } & \text { 600 } \
\text { Number of shipments with a claim } \geq \$ 100 & 200 & 100 \
\hline
\end{array}$$ The owner of Company B is hoping to use these data to show that her company is superior to Company A with regard to the percentage of claims filed. Which test would be used to properly analyze the data in this experiment?

Accepted Answer

A) The $\chi$2 test of a contingency table in a two-way contingency table. 
B) The $\chi$2 goodness-of-fitness test. 
C) The z-test for the difference in two proportions. 
D) The ANOVA F test for main treatment effect. 
A) The $\chi$2 test of a contingency table in a two-way contingency table. 
B) The $\chi$2 goodness-of-fitness test. 
C) The z-test for the difference in two proportions. 
D) The ANOVA F test for main treatment effect.

Question 8

In 2011, Brand A MP3 Players had 45% of the market, Brand B had 35%, and Brand C had 20%. This year the makers of brand C launched a heavy advertising campaign. A random sample of electronic stores shows that of 10,000 MP3 Players sold, 4,350 were Brand A, 3,450 were Brand B, and 2,200 were Brand C. Has the market changed? Test at $\alpha$ = 0.01.

Accepted Answer

H₀: p₁ = 0.45, p₂ = 0.35, p₃ = 0.20 H₁: At le

Question 9

The owner of a consumer products company asked a random sample of employees how they felt about the work they were doing. The following table gives a breakdown of their responses by age. Is there sufficient evidence to conclude that the level of job satisfaction is related to age? Use $\alpha$ = 0.10. $$\begin{array}{l}
\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\text { Rosponse }\
\begin{array} {| l | c c c | } 
\hline \text { Age } & \text { Very Interesting } & \text { Fairly Interestine } & \text { Not Interesting } \
\hline \text { Under 30 } & 31 & 24 & 13 \
\text { Between 30 and 50 } & 42 & 30 & 4 \
\text { Over 50 } & 32 & 21 & 3 \
\hline
\end{array}
\end{array}$$

Accepted Answer

H₀: Job satisfaction and age are independ

Question 10

NARRBEGIN: Seat Belts
Seat Belts
A study was conducted to determine whether the use of seat belts in vehicles depends on whether or not a child was present in the car. A sample of 1,000 people treated for injuries sustained from vehicle accidents was obtained, and each person was classified according to (1) child present (yes/no) and (2) seat belt usage (worn or not worn) during the accident. The data are shown in the table below. $$\begin{array} { | l | c c | } 
& { \text { Child present in car } } \
\hline \text { Seat Belts } & \text { NO } & \text { YES } \
\hline \text { Worn } & 83 & 200 \
\text { Not Worn } & 337 & 380 \
\hline
\end{array}$$ NARREND
-{Seat Belts Narrative} How many degrees of freedom are associated with the proper test in this experiment?

Accepted Answer

df = (2 -

Question 11

For a chi-squared distributed random variable with 10 degrees of freedom and a level of significance of 0.025, the chi-squared table value is 20.4831. Suppose the value of your test statistic is 16.857. This will lead you to reject the null hypothesis.

Accepted Answer

A) True 
 B)False

Question 12

The null hypothesis states that the sample data came from a normally distributed population. The researcher calculates the sample mean and the sample standard deviation from the data. The data arrangement consisted of five categories. Using $\alpha$ = 0.05, the appropriate critical value for this chi-squared test for normality is 5.99147.

Accepted Answer

A) True 
 B)False

Question 13

In the test of a contingency table, the expected cell frequencies must satisfy the rule of 5.

Accepted Answer

A) True 
 B)False

Question 14

If we want to conduct a one-tail test of a population proportion, we can employ:

Accepted Answer

A) z-test of a population proportion. 
B) the chi-squared test of a binomial experiment since z2 = $\chi$2. 
C) the chi-squared test of a contingency table. 
D) Both a and b 
A) z-test of a population proportion. 
B) the chi-squared test of a binomial experiment since z2 = $\chi$2. 
C) the chi-squared test of a contingency table. 
D) Both a and b

Question 15

The number of degrees of freedom associated with the chi-squared test for normality is the number of intervals used minus the number of parameters estimated from the data.

Accepted Answer

A) True 
 B)False

Question 16

All of the expected frequencies in a chi-squared goodness-of-fit test must be equal to each other.

Accepted Answer

A) True 
 B)False

Question 17

A large value of a chi-squared test statistic in a test of a contingency table leads you to conclude the two variables are ____________________.

Accepted Answer

The answer of A large value of a chi-squared test...

Question 18

NARRBEGIN: Seat Belts
Seat Belts
A study was conducted to determine whether the use of seat belts in vehicles depends on whether or not a child was present in the car. A sample of 1,000 people treated for injuries sustained from vehicle accidents was obtained, and each person was classified according to (1) child present (yes/no) and (2) seat belt usage (worn or not worn) during the accident. The data are shown in the table below. $$\begin{array} { | l | c c | } 
& { \text { Child present in car } } \
\hline \text { Seat Belts } & \text { NO } & \text { YES } \
\hline \text { Worn } & 83 & 200 \
\text { Not Worn } & 337 & 380 \
\hline
\end{array}$$ NARREND
-{Seat Belts Narrative} Which test would be used to properly analyze the data in this experiment?

Accepted Answer

@#LAT-DLM&² test of a

Question 19

If we want to perform a one-tail test of a population proportion p, we can employ either the z-test of p, or the chi-squared goodness-of-fit test.

Accepted Answer

A) True 
 B)False

Question 20

Which of the following statements is true for chi-squared tests?

Accepted Answer

A) Testing for equal proportions is identical to testing for goodness-of-fit. 
B) The number of degrees of freedom in a test of a contingency table with r rows and c columns is (r - 1)(c - 1). 
C) The number of degrees of freedom in a goodness-of-fit test with k categories is k - 1. 
D) All of these choices are true. 
A) Testing for equal proportions is identical to testing for goodness-of-fit. 
B) The number of degrees of freedom in a test of a contingency table with r rows and c columns is (r - 1)(c - 1). 
C) The number of degrees of freedom in a goodness-of-fit test with k categories is k - 1. 
D) All of these choices are true.

If the expected frequency e_i for any cell i is less than 5, we should:

The number of degrees of freedom for a contingency table with r rows and c columns is:

A sports preference poll showed the following data for adults and children: Favorite Sport gender Baseball Soccer Rugby Hockey Archery Adults 24 17 30 18 22 Children 21 20 22 12 28 Use the 5% level of significance and test to determine whether sports preferences depend on age group.

In conducting a chi-squared goodness-of-fit test, an essential condition is that all expected frequencies are at least five.

The squared difference between the observed and expected frequencies should be large if there is a significant difference between the proportions.

Which statistical technique is appropriate when we wish to analyze the relationship between two qualitative variables with two or more categories?

For a chi-squared distributed random variable with 10 degrees of freedom and a level of significance of 0.025, the chi-squared table value is 20.4831. Suppose the value of your test statistic is 16.857. This will lead you to reject the null hypothesis.

In the test of a contingency table, the expected cell frequencies must satisfy the rule of 5.

If we want to conduct a one-tail test of a population proportion, we can employ:

The number of degrees of freedom associated with the chi-squared test for normality is the number of intervals used minus the number of parameters estimated from the data.

All of the expected frequencies in a chi-squared goodness-of-fit test must be equal to each other.

A large value of a chi-squared test statistic in a test of a contingency table leads you to conclude the two variables are ____________________.

If we want to perform a one-tail test of a population proportion p, we can employ either the z-test of p, or the chi-squared goodness-of-fit test.

Which of the following statements is true for chi-squared tests?

What Is Statistics

Graphical Descriptive Techniques I

Graphical Descriptive Techniques II

Numerical Descriptive Techniques

Data Collection and Sampling

Probability

Random Variables and Discrete Probability Distributions

Continuous Probability Distributions

Sampling Distributions

Introduction to Estimation

Introduction to Hypothesis Testing

Inference About a Population

Inference About Comparing Two Populations

Analysis of Variance

Simple Linear Regression and Correlation

Multiple Regression

Filters

Exam 15: Chi-Squared Tests Optional

If the expected frequency ei for any cell i is less than 5, we should:

The number of degrees of freedom for a contingency table with r rows and c columns is:

A sports preference poll showed the following data for adults and children: Favorite Sport gender Baseball Soccer Rugby Hockey Archery Adults 24 17 30 18 22 Children 21 20 22 12 28 Use the 5% level of significance and test to determine whether sports preferences depend on age group.

In conducting a chi-squared goodness-of-fit test, an essential condition is that all expected frequencies are at least five.

The squared difference between the observed and expected frequencies should be large if there is a significant difference between the proportions.

Which statistical technique is appropriate when we wish to analyze the relationship between two qualitative variables with two or more categories?

For a chi-squared distributed random variable with 10 degrees of freedom and a level of significance of 0.025, the chi-squared table value is 20.4831. Suppose the value of your test statistic is 16.857. This will lead you to reject the null hypothesis.

In the test of a contingency table, the expected cell frequencies must satisfy the rule of 5.

If we want to conduct a one-tail test of a population proportion, we can employ:

The number of degrees of freedom associated with the chi-squared test for normality is the number of intervals used minus the number of parameters estimated from the data.

All of the expected frequencies in a chi-squared goodness-of-fit test must be equal to each other.

A large value of a chi-squared test statistic in a test of a contingency table leads you to conclude the two variables are ____________________.

If we want to perform a one-tail test of a population proportion p, we can employ either the z-test of p, or the chi-squared goodness-of-fit test.

Which of the following statements is true for chi-squared tests?

What Is Statistics

Graphical Descriptive Techniques I

Graphical Descriptive Techniques II

Numerical Descriptive Techniques

Data Collection and Sampling

Probability

Random Variables and Discrete Probability Distributions

Continuous Probability Distributions

Sampling Distributions

Introduction to Estimation

Introduction to Hypothesis Testing

Inference About a Population

Inference About Comparing Two Populations

Analysis of Variance

Simple Linear Regression and Correlation

Multiple Regression

Filters

If the expected frequency e_i for any cell i is less than 5, we should: