Exam 15: Chi-Squared Tests Optional
Exam 1: What Is Statistics43 Questions
Exam 2: Graphical Descriptive Techniques I93 Questions
Exam 3: Graphical Descriptive Techniques II140 Questions
Exam 4: Numerical Descriptive Techniques316 Questions
Exam 5: Data Collection and Sampling82 Questions
Exam 6: Probability237 Questions
Exam 7: Random Variables and Discrete Probability Distributions277 Questions
Exam 8: Continuous Probability Distributions215 Questions
Exam 9: Sampling Distributions154 Questions
Exam 10: Introduction to Estimation152 Questions
Exam 11: Introduction to Hypothesis Testing187 Questions
Exam 12: Inference About a Population149 Questions
Exam 13: Inference About Comparing Two Populations168 Questions
Exam 14: Analysis of Variance157 Questions
Exam 15: Chi-Squared Tests Optional175 Questions
Exam 16: Simple Linear Regression and Correlation301 Questions
Exam 17: Multiple Regression158 Questions
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To test for normality, the ____________________ hypothesis specifies probabilities of certain intervals within the normal distribution.
(Short Answer)
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A test statistic that lies in the far right tail of the chi-squared distribution indicates you will ____________________ H0.
(Short Answer)
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A chi-squared test statistic in a test of a contingency table that is equal to zero means:
(Multiple Choice)
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The chi-squared goodness-of-fit test compares the ____________________ frequencies in the table to the ____________________ frequencies based on the null hypothesis.
(Short Answer)
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Conduct a test to determine whether the two classifications A and B are independent, using the data in the accompanying table and = 0.05. 35 25 20 25 20 25
(Essay)
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NARRBEGIN: Students Absenteeism
Student Absenteeism
Consider a multinomial experiment involving n = 200 students of a large high school. The attendance department recorded the number of students who were absent during the weekdays. The null hypothesis to be tested is: H0: p1 = 0.10, p2 = 0.25, p3 = 0.30, p4 = 0.20, p5 = 0.15.NARREND
-{Student Absenteeism Narrative} Test the hypothesis at the 5% level of significance with the following frequencies:
Day of the Week Mon. Tues. Wed. Thurs. Fri. Number Absent 4 11 14 12 9
(Essay)
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A Deli proposes to serve 4 main Sandwiches. For planning purposes, the manager expects that the proportions of each that will be selected by her customers will be:
Selection Proportion Turkey 0.50 Roast Beef 0.20 Pastrami 0.10 Tuna 0.20 Of a random sample of 100 customers, 44 selected chicken, 24 selected roast beef, 13 selected Pastrami, and 10 selected tuna. Should the manager revise her estimates? Use = 0.01.
(Essay)
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The values of a chi-squared distribution are always ____________________ zero.
(Essay)
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The human resources manager of a consumer product company asked a random sample of employees how they felt about the work they were doing. The following table gives a breakdown of their responses by whether the employee is part time or full time (aka work status). Do the data provide sufficient evidence to conclude that the level of job satisfaction is related to their work status? Use = 0.10. Response Gender Very Interesting Fairly Interesting Not Interesting Full time 70 41 9 Part time 35 34 11
(Essay)
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If there are only two categories, the chi-squared goodness-of-fit test is the same as the z-test for p, the population proportion (as long as the sample/cell sizes meet the conditions).
(True/False)
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NARRBEGIN: Students Absenteeism
Student Absenteeism
Consider a multinomial experiment involving n = 200 students of a large high school. The attendance department recorded the number of students who were absent during the weekdays. The null hypothesis to be tested is: H0: p1 = 0.10, p2 = 0.25, p3 = 0.30, p4 = 0.20, p5 = 0.15.NARREND
-{Student Absenteeism Narrative} Test the hypothesis at the 5% level of significance with the following frequencies:
Day of the Week Mon. Tues. Wed. Thurs. Fri Number Absent 16 44 56 48 36
(Essay)
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There are two critical factors in identifying the technique used when the data are nominal. The first is the problem objective. The second is the number of ____________________ that nominal variable can assume.
(Short Answer)
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The number of degrees of freedom in a chi-squared test for normality, where the number of standardized intervals is 5 and there are 2 population parameters to be estimated from the data, is equal to:
(Multiple Choice)
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In a goodness-of-fit test, H0 lists specific values for proportions and the test of a contingency table does not.
(True/False)
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The rule of five states that in order to conduct the chi-squared goodness-of-fit test, the ____________________ value for each cell must be five or more.
(Short Answer)
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Mathematical statisticians have established that if we square the value of z, the test statistic for the test of one proportion p, we produce the 2 statistic. That is, z2 = 2.
(True/False)
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A small chi-squared test statistic in a goodness-of-fit test supports the null hypothesis.
(True/False)
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The rule of ____________________ states that in order to conduct the chi-squared goodness-of-fit test, the expected value for each cell must be ____________________ or more.
(Short Answer)
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To test for normality, the ____________________ hypothesis is that at least two proportions differ from their specified values.
(Short Answer)
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