Question 1

Write an equation of the line passing through the given points. Write the equation in standard form Ax + By = C.
- (-4,0)  and  (9,-3)

Accepted Answer

A)   -3 x-13y=12 
B)   4 x-12y=0 
C)   3 x-13y=12 
D)   -4 x+12y=0 
A)   -3 x-13y=12 
B)   4 x-12y=0 
C)   3 x-13y=12 
D)   -4 x+12y=0

Question 2

Find the domain and the range of the relation. Also determine whether the relation is a function.
-

Accepted Answer

A)  Domain: $( - \infty , \infty )$, range: $( - \infty , \infty )$; function 
B)  Domain: [3], range: [3]; not a function 
C)  Domain: $( - \infty , \infty )$ , range: [3]; function 
D)  Domain: [3], range: $( - \infty , \infty )$ ; not a function 
A)  Domain: $( - \infty , \infty )$, range: $( - \infty , \infty )$; function 
B)  Domain: [3], range: [3]; not a function 
C)  Domain: $( - \infty , \infty )$ , range: [3]; function 
D)  Domain: [3], range: $( - \infty , \infty )$ ; not a function

Question 3

Solve the problem.
-When a tow truck is called, the cost of the service is given by the linear function y = 3x + 55, where y is in dollars and x is the number of miles the car is towed. Find and interpret the slope and y-intercept of the linear
Equation.

Accepted Answer

A)  m = 3; The number of miles the car is towed increases 3 miles for every dollar spent on the service. b = 55; The tow truck will tow the car 55 miles for no cost. 
B)  m = 55; The number of miles the car is towed increases 55 miles for every dollar spent on the service. b = 3; The tow truck will tow the car 3 miles for no cost. 
C)  m = 55; The cost of the service increases $55 every mile the car is towed. b = 3; The cost of the service is $3 if the car is not towed. 
D)  m = 3; The cost of the service increases $3 every mile the car is towed. b = 55; The cost of the service is $55 if the car is not towed. 
A)  m = 3; The number of miles the car is towed increases 3 miles for every dollar spent on the service. b = 55; The tow truck will tow the car 55 miles for no cost. 
B)  m = 55; The number of miles the car is towed increases 55 miles for every dollar spent on the service. b = 3; The tow truck will tow the car 3 miles for no cost. 
C)  m = 55; The cost of the service increases $55 every mile the car is towed. b = 3; The cost of the service is $3 if the car is not towed. 
D)  m = 3; The cost of the service increases $3 every mile the car is towed. b = 55; The cost of the service is $55 if the car is not towed.

Question 4

Find the domain and range.
-$\left\{ ( 8.66,15.86 ) , ( 8.666 , - 15.9 ) , \left( \frac { 9 } { 7 } , 0 \right) , ( 1.29 , - 8 ) \right\}$

Accepted Answer

A)  
$\text { Domain: } \left\{ 8.66,8.666 , \frac { 9 } { 7 } , 1.29 \right\} ; \text { range: } \{ 15.86 , - 15.9,0 , - 8 \}$ 
B)  
$\text { Domain: } \{ 8.66,8.666,1.29 \} \text {; range: } \{ 15.86 , - 15.9,0 \}$ 
C)  
$\text { Domain: } \{ 15.86 , - 15.9,0 \} \text {; range: } \{ 8.66,8.666,1.29 \}$ 
D) 
 $\text { Domain: } \{ 15.86 , - 15.9,0 , - 8 \} ; \text { range: } \left\{ 8.66,8.666 , \frac { 9 } { 7 } , 1.29 \right\}$ 
A)  
$\text { Domain: } \left\{ 8.66,8.666 , \frac { 9 } { 7 } , 1.29 \right\} ; \text { range: } \{ 15.86 , - 15.9,0 , - 8 \}$ 
B)  
$\text { Domain: } \{ 8.66,8.666,1.29 \} \text {; range: } \{ 15.86 , - 15.9,0 \}$ 
C)  
$\text { Domain: } \{ 15.86 , - 15.9,0 \} \text {; range: } \{ 8.66,8.666,1.29 \}$ 
D) 
 $\text { Domain: } \{ 15.86 , - 15.9,0 , - 8 \} ; \text { range: } \left\{ 8.66,8.666 , \frac { 9 } { 7 } , 1.29 \right\}$

Question 5

Find the slope of the line.
-$$x = 3$$

Accepted Answer

A)  $- 3$ 
B)  0 
C)  3 
D)  Undefined 
A)  $- 3$ 
B)  0 
C)  3 
D)  Undefined

Question 6

Use the slope-intercept form of the linear equation to write the equation of the line with the given slope and y-intercept.
-Slope $- \frac { 2 } { 5 } ; y$-intercept $( 0,5 )$

Accepted Answer

A)  $y = \frac { 2 } { 5 } x - 5$ 
B)  $y = - \frac { 2 } { 5 } x + 5$ 
C)  $y = - \frac { 2 } { 5 } x - 5$ 
D)  $y = \frac { 2 } { 5 } x + 5$ 
A)  $y = \frac { 2 } { 5 } x - 5$ 
B)  $y = - \frac { 2 } { 5 } x + 5$ 
C)  $y = - \frac { 2 } { 5 } x - 5$ 
D)  $y = \frac { 2 } { 5 } x + 5$

Question 7

(0, 6)

Accepted Answer

A)  Quadrant I 
B)  Quadrant II 
C)   x-axis 
D)   y-axis 
A)  Quadrant I 
B)  Quadrant II 
C)   x-axis 
D)   y-axis

Question 8

Solve.
-The monthly cost of a certain long distance service is given by the linear function C(t) = 0.08t + 5.95 where C(t) is in dollars and t is the amount of time in minutes called in a month. Find the cost of calling long distance for 200
Minutes in a month.

Accepted Answer

A)  $21.95 
B)  $25.95 
C)  $16.00 
D)  $20.95 
A)  $21.95 
B)  $25.95 
C)  $16.00 
D)  $20.95

Write an equation of the line passing through the given points. Write the equation in standard form Ax + By = C. - (-4,0) and (9,-3)

Find the domain and the range of the relation. Also determine whether the relation is a function. -

Solve the problem. -When a tow truck is called, the cost of the service is given by the linear function y = 3x + 55, where y is in dollars and x is the number of miles the car is towed. Find and interpret the slope and y-intercept of the linear Equation.

Find the domain and range. - $\left\{ ( 8.66,15.86 ) , ( 8.666 , - 15.9 ) , \left( \frac { 9 } { 7 } , 0 \right) , ( 1.29 , - 8 ) \right\}$

Find the slope of the line. - $x = 3$

Use the slope-intercept form of the linear equation to write the equation of the line with the given slope and y-intercept. -Slope $- \frac { 2 } { 5 } ; y$ -intercept $( 0,5 )$

(0, 6)

Solve. -The monthly cost of a certain long distance service is given by the linear function C(t) = 0.08t + 5.95 where C(t) is in dollars and t is the amount of time in minutes called in a month. Find the cost of calling long distance for 200 Minutes in a month.

Real Numbers and Algebraic Expressions

Equations, Inequalities, and Problem Solving

Systems of Equations and Inequalities

Polynomials and Polynomial Functions

Rational Expressions

Rational Exponents, Radicals, and Complex Numbers

Quadratic Equations and Functions

Exponential and Logarithmic Functions

Conic Sections

Fractions

Filters

Exam 3: Graphs and Functions

Write an equation of the line passing through the given points. Write the equation in standard form Ax + By = C. - (-4,0) and (9,-3)

Find the domain and the range of the relation. Also determine whether the relation is a function. -

Solve the problem. -When a tow truck is called, the cost of the service is given by the linear function y = 3x + 55, where y is in dollars and x is the number of miles the car is towed. Find and interpret the slope and y-intercept of the linear Equation.

Find the domain and range. - {(8.66,15.86),(8.666,−15.9),(97,0),(1.29,−8)}\left\{ ( 8.66,15.86 ) , ( 8.666 , - 15.9 ) , \left( \frac { 9 } { 7 } , 0 \right) , ( 1.29 , - 8 ) \right\}{(8.66,15.86),(8.666,−15.9),(79​,0),(1.29,−8)}

Find the slope of the line. - x=3x = 3x=3

Use the slope-intercept form of the linear equation to write the equation of the line with the given slope and y-intercept. -Slope −25;y- \frac { 2 } { 5 } ; y−52​;y -intercept (0,5)( 0,5 )(0,5)

(0, 6)

Solve. -The monthly cost of a certain long distance service is given by the linear function C(t) = 0.08t + 5.95 where C(t) is in dollars and t is the amount of time in minutes called in a month. Find the cost of calling long distance for 200 Minutes in a month.

Real Numbers and Algebraic Expressions

Equations, Inequalities, and Problem Solving

Systems of Equations and Inequalities

Polynomials and Polynomial Functions

Rational Expressions

Rational Exponents, Radicals, and Complex Numbers

Quadratic Equations and Functions

Exponential and Logarithmic Functions

Conic Sections

Fractions

Filters

Find the domain and range. - $\left\{ ( 8.66,15.86 ) , ( 8.666 , - 15.9 ) , \left( \frac { 9 } { 7 } , 0 \right) , ( 1.29 , - 8 ) \right\}$

Find the slope of the line. - $x = 3$

Use the slope-intercept form of the linear equation to write the equation of the line with the given slope and y-intercept. -Slope $- \frac { 2 } { 5 } ; y$ -intercept $( 0,5 )$