Question 1

Find the indicated sum. Use the formula for the sum of the first n terms of a geometric sequence.
-$$\sum _ { i = 1 } ^ { 5 } 3 \cdot 4 i$$

Accepted Answer

A)  4092 
B)  7710 
C)  268 
D)  252 
A)  4092 
B)  7710 
C)  268 
D)  252

Question 2

Use the Formula for the General Term of a Geometric Sequence
-Find a9 when $a _ { 1 } = 4 , r = 2$.

Accepted Answer

A)  1024 
B)  2048 
C)  1028 
D)  20 
A)  1024 
B)  2048 
C)  1028 
D)  20

Question 3

Use the Formula for the Sum of an Infinite Geometric Series
-$$5 + \frac { 5 } { 2 } + \frac { 5 } { 4 } + \frac { 5 } { 8 } + \ldots$$

Accepted Answer

A)  10 
B)  $\frac { 15 } { 2 }$ 
C)  $\frac { 5 } { 2 }$ 
D)  does not exist 
A)  10 
B)  $\frac { 15 } { 2 }$ 
C)  $\frac { 5 } { 2 }$ 
D)  does not exist

Question 4

Use Recursion Formulas
-$a _ { 1 } = 3$ and $a _ { n } = 2 a _ { n - 1 } - 4$ for $n \geq 2$

Accepted Answer

A)  $3,2,0 , - 4$ 
B)  $3,2,8,20$ 
C)  $3,6,12,24$ 
D)  $3,10,24,52$ 
A)  $3,2,0 , - 4$ 
B)  $3,2,8,20$ 
C)  $3,6,12,24$ 
D)  $3,10,24,52$

Find the indicated sum. Use the formula for the sum of the first n terms of a geometric sequence. - $\sum _ { i = 1 } ^ { 5 } 3 \cdot 4 i$

Use the Formula for the General Term of a Geometric Sequence -Find a9 when $a _ { 1 } = 4 , r = 2$ .

Use the Formula for the Sum of an Infinite Geometric Series - $5 + \frac { 5 } { 2 } + \frac { 5 } { 4 } + \frac { 5 } { 8 } + \ldots$

Use Recursion Formulas - $a _ { 1 } = 3$ and $a _ { n } = 2 a _ { n - 1 } - 4$ for $n \geq 2$

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Exam 11: Sequences, Induction, and Probability

Find the indicated sum. Use the formula for the sum of the first n terms of a geometric sequence. - ∑i=153⋅4i\sum _ { i = 1 } ^ { 5 } 3 \cdot 4 i∑i=15​3⋅4i

Use the Formula for the General Term of a Geometric Sequence -Find a9 when a1=4,r=2a _ { 1 } = 4 , r = 2a1​=4,r=2 .

Use the Formula for the Sum of an Infinite Geometric Series - 5+52+54+58+…5 + \frac { 5 } { 2 } + \frac { 5 } { 4 } + \frac { 5 } { 8 } + \ldots5+25​+45​+85​+…

Use Recursion Formulas - a1=3a _ { 1 } = 3a1​=3 and an=2an−1−4a _ { n } = 2 a _ { n - 1 } - 4an​=2an−1​−4 for n≥2n \geq 2n≥2